### Magnetic Force on a Speaker's Voice CoilThe voice coil of a speaker has a diameter of 0.0025 m, contains 55 turns of wire, and is placed in a 0.10-T magnetic field. The current in the voice coil is 2.0 A.(a) **Determine the magnetic force that acts on the coil and the cone.**(b) **The voice coil and cone have a combined mass of 0.0200 kg. Find their acceleration.**#### Diagram ExplanationThe provided diagram consists of three main parts:1. **Left Section:** - This shows a permanent magnet with labeled components. - A voice coil is depicted adjacent to a speaker cone. - Black panel of receiver connected via a wire to the speaker terminals.2. **Right Section:** - Demonstrates the magnetic field and the voice coil in greater detail. - A uniform magnetic field region labeled "Magnetic field" is shown. - The voice coil in the magnetic field is illustrated with force vectors denoted by \( \mathbf{F} \).#### Solutions Breakdown:1. **Determine the Magnetic Force:**Use the formula for the magnetic force on a current-carrying conductor in a magnetic field:\[ F = n \cdot L \cdot I \cdot B \]where:- \( n \) = number of turns (55)- \( L \) = length of one turn (circumference of the coil) \( = \pi \times \text{diameter} \)- \( I \) = current (2.0 A)- \( B \) = magnetic field (0.10 T)Length of one turn \( L \):\[ L = \pi \times 0.0025 \, \text{m} \approx 0.00785 \, \text{m} \]Now, calculating the total force \( F \):\[ F = 55 \times 0.00785 \, \text{m} \times 2.0 \, \text{A} \times 0.10 \, \text{T} = 55 \times 0.00157 \, \text{N} = 0.08635 \, \text{N} \]2. **Find the Acceleration:**Use Newton's second law:\[ F = m \cd

Solution: a). The magnetic force acting on the coil is given by the vector product of the current…

Answered: The voice coil of a speaker has a…

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