The velocity vs. time graph for an object moving along a straight path is shown in the figure below. A function is plotted on a coordinate plane, with the horizontal axis labeled t (s) ranging from 0 to 21 s and the vertical axis labeled v (m/s) ranging from −9 m/s to 9 m/s. The function enters the viewing window at (0, −8) and goes horizontally rightward to the approximate point (5, −8). Then the function curves upward and extends up and right in a straight line to the approximate point (15, 8). The function then curves rightward and goes horizontally rightward to the point (20, 8), where the function ends.(i) Find the average acceleration of this object during the following time intervals.(a) 0 s to 5.0 sYour response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.m/s2(b) 5.0 s to 15 sm/s2(c) 0 s to 20 sYour response differs from the correct answer by more than 10%. Double check your calculations.m/s2(ii) Find the instantaneous accelerations at the following times.(a) 2.0 sYour response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.m/s2(b) 10 sm/s2(c) 18 sm/s2 The graph depicted on this page is a velocity-time graph, which represents how the velocity of an object changes over a period of time. ### Components of the Graph:1. **Axes**: - **Horizontal Axis (t in seconds)**: This axis represents time in seconds. The values range from 0 to 20 seconds. - **Vertical Axis (v in meters per second)**: This axis represents velocity in meters per second. The values range from -8 to 8 m/s.2. **Data Line**: - The line on the graph is plotted in orange. It starts from the velocity of -8 m/s at 0 seconds, indicating that the object is initially moving backwards at 8 m/s. - The velocity then increases, resulting in the line rising diagonally upwards until it reaches 0 m/s at about 5 seconds, which implies the object has stopped moving at this instant. - The line continues to rise until it reaches 8 m/s at approximately 10 seconds, showing that the object has reversed direction and is now moving forward with a velocity of 8 m/s. - From 10 seconds onward, the object maintains this constant velocity of 8 m/s until the end of the observed time period at 20 seconds.### Interpretation:- The initial negative velocity indicates that the object is initially moving in the opposite direction.- As the line slopes upwards, it shows that the object is decelerating until it comes to a stop at 0 velocity.- The continued upward slope demonstrates acceleration in the opposite direction until the object reaches a constant positive velocity.- A horizontal line at the velocity of 8 m/s denotes uniform motion; the object continues to move at a steady pace.This graph provides a clear visual representation of the changes in velocity an object undergoes over a period of time, illustrating key concepts in kinematics such as acceleration, deceleration, and uniform motion.

In a velocity verse time curve, the slope of the curve represents the acceleration of the object.…

The velocity vs. time graph for an object moving along a straight path is shown in the figure below. A function is plotted on a coordinate plane, with the horizontal axis labeled t (s) ranging from 0 to 21 s and the vertical axis labeled v (m/s) ranging from −9 m/s to 9 m/s. The function enters the viewing window at (0, −8) and goes horizontally rightward to the approximate point (5, −8). Then the function curves upward and extends up and right in a straight line to the approximate point (15, 8). The function then curves rightward and goes horizontally rightward to the point (20, 8), where the function ends. (i) Find the average acceleration of this object during the following time intervals. (a) 0 s to 5.0 s Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.m/s2 (b) 5.0 s to 15 s m/s2 (c) 0 s to 20 s Your response differs from the correct answer by more than 10%. Double check your calculations.m/s2 (ii) Find the instantaneous accelerations at the following times. (a) 2.0 s Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.m/s2 (b) 10 s m/s2 (c) 18 s m/s2

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The velocity vs. time graph for an object moving along a straight path is shown in the figure below.

A function is plotted on a coordinate plane, with the horizontal axis labeled t (s) ranging from 0 to 21 s and the vertical axis labeled v (m/s) ranging from −9 m/s to 9 m/s. The function enters the viewing window at (0, −8) and goes horizontally rightward to the approximate point (5, −8). Then the function curves upward and extends up and right in a straight line to the approximate point (15, 8). The function then curves rightward and goes horizontally rightward to the point (20, 8), where the function ends.

(i) Find the average acceleration of this object during the following time intervals.

(a)    0 s to 5.0 s

Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.m/s²

(b)    5.0 s to 15 s
m/s²

(c)    0 s to 20 s

Your response differs from the correct answer by more than 10%. Double check your calculations.m/s²

(ii) Find the instantaneous accelerations at the following times.

(a)    2.0 s

Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.m/s²

(b)    10 s
m/s²

(c)    18 s
m/s²

The graph depicted on this page is a velocity-time graph, which represents how the velocity of an object changes over a period of time.

### Components of the Graph:

1. **Axes**:
- **Horizontal Axis (t in seconds)**: This axis represents time in seconds. The values range from 0 to 20 seconds.
- **Vertical Axis (v in meters per second)**: This axis represents velocity in meters per second. The values range from -8 to 8 m/s.

2. **Data Line**:
- The line on the graph is plotted in orange. It starts from the velocity of -8 m/s at 0 seconds, indicating that the object is initially moving backwards at 8 m/s.
- The velocity then increases, resulting in the line rising diagonally upwards until it reaches 0 m/s at about 5 seconds, which implies the object has stopped moving at this instant.
- The line continues to rise until it reaches 8 m/s at approximately 10 seconds, showing that the object has reversed direction and is now moving forward with a velocity of 8 m/s.
- From 10 seconds onward, the object maintains this constant velocity of 8 m/s until the end of the observed time period at 20 seconds.

### Interpretation:

- The initial negative velocity indicates that the object is initially moving in the opposite direction.
- As the line slopes upwards, it shows that the object is decelerating until it comes to a stop at 0 velocity.
- The continued upward slope demonstrates acceleration in the opposite direction until the object reaches a constant positive velocity.
- A horizontal line at the velocity of 8 m/s denotes uniform motion; the object continues to move at a steady pace.

This graph provides a clear visual representation of the changes in velocity an object undergoes over a period of time, illustrating key concepts in kinematics such as acceleration, deceleration, and uniform motion.

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