The velocity of a particle moving in the x-y plane is given next 0.02 s is (4.0i + 6.0j) m/s2. Determine the velocity v vector and the velocity vector at t = 3.67 s. Answers: v = (i 0= = i i+ IM i
The velocity of a particle moving in the x-y plane is given next 0.02 s is (4.0i + 6.0j) m/s2. Determine the velocity v vector and the velocity vector at t = 3.67 s. Answers: v = (i 0= = i i+ IM i
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![The velocity of a particle moving in the x-y plane is given by (6.12i + 3.24j) m/s at time t = 3.65 s. Its average acceleration during the
next 0.02 s is (4.0i + 6.0j) m/s². Determine the velocity v of the particle at t = 3.67 s and the angle between the average-acceleration
vector and the velocity vector at t = 3.67 s.
Answers:
V = ( i
8= i
it i
j) m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe27fc493-1d19-42fe-a65b-f193dd7a2b3e%2Fbe7f9e24-6a23-4dda-ad81-c11b218a0f7a%2Fl7zkhmq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The velocity of a particle moving in the x-y plane is given by (6.12i + 3.24j) m/s at time t = 3.65 s. Its average acceleration during the
next 0.02 s is (4.0i + 6.0j) m/s². Determine the velocity v of the particle at t = 3.67 s and the angle between the average-acceleration
vector and the velocity vector at t = 3.67 s.
Answers:
V = ( i
8= i
it i
j) m/s
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