The velocity of a particle moving along a line is given by v(t) = t³ – 4ť² meters per second. Find the displacement of the particle during the time interval between -2 and 6 seconds. Displacement = (Include the correct units.) To find the total distance traveled by the particle during the time interval from -2 to 6 seconds, we must split the integral of the absolute value of velocity into a sum of two integrals Total distance traveled = %3D |t3 – 4t2| dt = | vi(t) dt + | v2 (t) dt - where vi (t) and v2 (t) are functions and k is a number such that v1(t) = (Absolute values are not allowed.)

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