The velocity of a package traveling along the axis is shown as a function of time in the figure below. If the package is at x = 0 when t= 0, answer the following. Vx (m/s) 20 10 t (s) -10 (a) What is the object's acceleration (in m/s2) between 0 and 4.00 s? (Indicate the direction with the sign of your answer.) V m/s2 (b) What is the object's acceleration (in m/s2) between 4.00 s and 9.00 s? (Indicate the direction with the sign of your answer.) 6 From the plot, we see that the velocity is changing at a constant rate during the time interval of interest. The acceleration is the slope of the straight line between times of interest. m/s? (c) What is the object's acceleration (in m/s2) between 12.0 s and 18.0 s? (Indicate the direction with the sign of your answer.) 3 The acceleration during the time interval of interest may be determined by finding the slope of the velocity-versus-time plot during this time. Looking at the graph, what is the slope of this line? m/s?

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The velocity of a package traveling along the axis is shown as a function of time in the figure below. If the package is at x = 0 when t = 0, answer the following.
Vx (m/s)
20
10
t (s)
10
15
-10
(a) What is the object's acceleration (in m/s2) between 0 and 4.00 s? (Indicate the direction with the sign of your answer.)
v m/s2
(b) What is the object's acceleration (in m/s?) between 4.00 s and 9.00 s? (Indicate the direction with the sign of your answer.)
6
From the plot, we see that the velocity is changing at a constant rate during the time interval of interest. The acceleration is the slope of the straight line between the times of interest. m/s
(c) What is the object's acceleration (in m/s?) between 12.0 s and 18.0 s? (Indicate the
with
sign of your answer.)
|-3
The acceleration during the time interval of interest may be determined by finding the slope of the velocity-versus-time plot during this time. Looking at the graph, what is the slope of this line? m/s?
(d) At what time(s) (in s) is the object moving with the lowest speed? (If there is more than one time, enter the times from smallest to largest. If there is only one time, enter 0 in the second box.)
v s (smaller value)
s (larger value)
6
18
(e) At what time (in s) is the object farthest from x = 0?
18
(f) What is the final position x (in m) of the object at t = 18 s?
84
The final position is the magnitude of the total displacement vector. We first have a negative displacement and then a positive displacement. We can determine the total displacement from the negative and positive displacement
can determine the final position. m
(g) Through what total distance (in m) has the object moved between t = 0 and t = 18 s?
204
The total distance traveled is the sum of the magnitude of the displacement vectors Note that the travel includes a negative and a positive displacement vector The disnlacement can be positive or negative but since the distan
Transcribed Image Text:The velocity of a package traveling along the axis is shown as a function of time in the figure below. If the package is at x = 0 when t = 0, answer the following. Vx (m/s) 20 10 t (s) 10 15 -10 (a) What is the object's acceleration (in m/s2) between 0 and 4.00 s? (Indicate the direction with the sign of your answer.) v m/s2 (b) What is the object's acceleration (in m/s?) between 4.00 s and 9.00 s? (Indicate the direction with the sign of your answer.) 6 From the plot, we see that the velocity is changing at a constant rate during the time interval of interest. The acceleration is the slope of the straight line between the times of interest. m/s (c) What is the object's acceleration (in m/s?) between 12.0 s and 18.0 s? (Indicate the with sign of your answer.) |-3 The acceleration during the time interval of interest may be determined by finding the slope of the velocity-versus-time plot during this time. Looking at the graph, what is the slope of this line? m/s? (d) At what time(s) (in s) is the object moving with the lowest speed? (If there is more than one time, enter the times from smallest to largest. If there is only one time, enter 0 in the second box.) v s (smaller value) s (larger value) 6 18 (e) At what time (in s) is the object farthest from x = 0? 18 (f) What is the final position x (in m) of the object at t = 18 s? 84 The final position is the magnitude of the total displacement vector. We first have a negative displacement and then a positive displacement. We can determine the total displacement from the negative and positive displacement can determine the final position. m (g) Through what total distance (in m) has the object moved between t = 0 and t = 18 s? 204 The total distance traveled is the sum of the magnitude of the displacement vectors Note that the travel includes a negative and a positive displacement vector The disnlacement can be positive or negative but since the distan
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