The Varners live on a corner lot. Often, children cut across their lot to save walking distance. The diagram to the right represents the corner lot. The children's path is represented by a dashed line. Approximate the walking distance that is saved by cutting across their property instead of walking around the lot. 38 feet x+2 The walking distance that is saved by cutting across the lot is Round the final answer to the nearest integer as needed. Round all intermediate values to the nearest thousandth as needed.)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The Varners live on a corner lot. Often, children cut across their lot to save walking distance. The diagram to the right represents the corner lot. The children's path is represented by a dashed line. Approximate the walking distance that is saved by cutting across their property instead of walking around the lot.

The diagram shows a right triangle with:

- One leg labeled \(x\).
- The other leg labeled \(x + 2\).
- The hypotenuse (dashed line) labeled 38 feet.

The task is to calculate the walking distance saved by using the hypotenuse instead of the two legs.

The walking distance that is saved by cutting across the lot is \([ \ \ ]\) \([ \ \ ]\).

(Round the final answer to the nearest integer as needed. Round all intermediate values to the nearest thousandth as needed.)
Transcribed Image Text:The Varners live on a corner lot. Often, children cut across their lot to save walking distance. The diagram to the right represents the corner lot. The children's path is represented by a dashed line. Approximate the walking distance that is saved by cutting across their property instead of walking around the lot. The diagram shows a right triangle with: - One leg labeled \(x\). - The other leg labeled \(x + 2\). - The hypotenuse (dashed line) labeled 38 feet. The task is to calculate the walking distance saved by using the hypotenuse instead of the two legs. The walking distance that is saved by cutting across the lot is \([ \ \ ]\) \([ \ \ ]\). (Round the final answer to the nearest integer as needed. Round all intermediate values to the nearest thousandth as needed.)
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