The vapor pressure of water at 90°C is 0.692 atm, What is the vapor pressure (in atm) of a solution made by dissolving 2.91 mole(s) of CsF(s) in 1.00 kg of water (18.015 g/mol)? Assume that Raoult's law applies.

The vapor pressure of water at 90°C is 0.692 atm, What is the vapor pressure (in atm) of a solution made by dissolving 2.91 mole(s) of CsF(s) in 1.00 kg of water (18.015 g/mol)? Assume that Raoult's law applies.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

The vapor pressure of water at 90°C is 0.692 atm, What is the vapor pressure (in atm) of a solution made by dissolving 2.91 mole(s) of
CsF(S) in 1.00 kg of water (18.015 g/mol)? Assume that Raoult's law applies.
0.626 atm
0.658 atmi
0.692 atm
0.765 atm
none of these

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