The vapor pressure of water at 25 °C is 0.0313 atm. Calculate the vapor pressure in mmHg and torr. Round each of your answers to 3 significant digits. I mmHg torr
The vapor pressure of water at 25 °C is 0.0313 atm. Calculate the vapor pressure in mmHg and torr. Round each of your answers to 3 significant digits. I mmHg torr
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
The vapor pressure of water at 25 °C is 0.0313 atm. Calculate the vapor pressure in mmHg and torr. Round each of your answers to 3 significant digits.
**Answer Fields:**
- mmHg: [Blank field for input]
- torr: [Blank field for input]
**Interactive Features:**
- A checkbox labeled "x10" (possibly for adjusting scientific notation).
- Three buttons:
- "x" (could represent an action to clear inputs)
- "↻" (refresh or reset)
- "?" (help or information)
**Explanation for Teachers:**
At 25 °C, the given vapor pressure of water is in atmospheres. This pressure needs to be converted into two other units: mmHg and torr. These conversions are typically performed using the relationships:
- 1 atm = 760 mmHg
- 1 atm = 760 torr
By multiplying the given pressure in atm by 760, you obtain the pressure in both mmHg and torr, since these units are equivalent. The result must be rounded to three significant digits as per the instructions.
**Use Case:**
This example can be integrated into lessons on unit conversion in chemistry, specifically focusing on gas laws and the properties of gases. It also enhances understanding of significant figures, which is crucial for accurate scientific calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8c26f4d-51be-4af6-b903-84d467956966%2F1444e1fa-2620-4aec-a4bc-5b174de5f323%2Ftw9ln1p_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
The vapor pressure of water at 25 °C is 0.0313 atm. Calculate the vapor pressure in mmHg and torr. Round each of your answers to 3 significant digits.
**Answer Fields:**
- mmHg: [Blank field for input]
- torr: [Blank field for input]
**Interactive Features:**
- A checkbox labeled "x10" (possibly for adjusting scientific notation).
- Three buttons:
- "x" (could represent an action to clear inputs)
- "↻" (refresh or reset)
- "?" (help or information)
**Explanation for Teachers:**
At 25 °C, the given vapor pressure of water is in atmospheres. This pressure needs to be converted into two other units: mmHg and torr. These conversions are typically performed using the relationships:
- 1 atm = 760 mmHg
- 1 atm = 760 torr
By multiplying the given pressure in atm by 760, you obtain the pressure in both mmHg and torr, since these units are equivalent. The result must be rounded to three significant digits as per the instructions.
**Use Case:**
This example can be integrated into lessons on unit conversion in chemistry, specifically focusing on gas laws and the properties of gases. It also enhances understanding of significant figures, which is crucial for accurate scientific calculations.
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