Answered: The vapor pressure of mercury at 298 K…

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter14: Liquids And Solids

Section: Chapter Questions

Problem 26A

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Question

2.) The vapor pressure of mercury at 298 K is 0.00270 mmHg. If the normal boiling point of mercury is 630 K,
what is the heat of vaporization of mercury?

Expert Solution

Introduction

Use Clausius Clapeyron equation to solve this,

$\ln (\frac{P_{1}}{P_{2}}) = \frac{Δ H_{v a p}}{R} (\frac{1}{T_{2}} - \frac{1}{T_{1}})$

Given that,
T₁ = 298 K
P₁ = 0.00270 mm Hg
T₂ = 630 K
At normal boiling point vapor pressure P₂ = 760 mm Hg
R = 8.314 J/mol K

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