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The values of the components in the circuit are L = 163 mH, R, = 410 N, R, = 340 N, and E = 10.0 V. Use downward as the positive dire R1 R2 L (a) immediately after the switch is closed (after being open a long time)... ..the current through the inductor L = 0 mA ..the current through R, I2 = 13.33 mA (b) a long time after the switch has been closed... .the current through the inductor 1 = 24.39 mA ..the current through R2 mA (c) immediately after the switch is open (after being closed a long time)... .the current through the inductor mA .the current through R2 mA (d) a time 4.794e-04 s after the switch is open.. .the current through the inductor mA ..the current through R2 I2 = | mA ll

The values of the components in the circuit are L = 163 mH, R, = 410 N, R, = 340 N, and E = 10.0 V. Use downward as the positive dire R1 R2 L (a) immediately after the switch is closed (after being open a long time)... ..the current through the inductor L = 0 mA ..the current through R, I2 = 13.33 mA (b) a long time after the switch has been closed... .the current through the inductor 1 = 24.39 mA ..the current through R2 mA (c) immediately after the switch is open (after being closed a long time)... .the current through the inductor mA .the current through R2 mA (d) a time 4.794e-04 s after the switch is open.. .the current through the inductor mA ..the current through R2 I2 = | mA ll

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Answer questions C and D, Thank you

The values of the components in the circuit are L = 163 mH, R, = 410 N, R, = 340 N, and E = 10.0 V. Use downward as the positive direction for all currents. Find.. R R2 (a) immediately after the switch is closed (after being open a long time)... ..the current through the inductor L = 0 mA ..the current through R, I, = 13.33 (b) a long time after the switch has been closed... ...the current through the inductor I = 24.39 ..the current through R2 V MA (c) immediately after the switch is open (after being closed a long time)... ..the current through the inductor mA ..the current through R, mA (d) a time 4.794e-04 s after the switch is open.... ...the current through the inductor ..the current through R, I2 = |
Transcribed Image Text:The values of the components in the circuit are L = 163 mH, R, = 410 N, R, = 340 N, and E = 10.0 V. Use downward as the positive direction for all currents. Find.. R R2 (a) immediately after the switch is closed (after being open a long time)... ..the current through the inductor L = 0 mA ..the current through R, I, = 13.33 (b) a long time after the switch has been closed... ...the current through the inductor I = 24.39 ..the current through R2 V MA (c) immediately after the switch is open (after being closed a long time)... ..the current through the inductor mA ..the current through R, mA (d) a time 4.794e-04 s after the switch is open.... ...the current through the inductor ..the current through R, I2 = |
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