The values of a function are 1, 1.64603, 3.61628, 4.94562 corresponding to the values of the argument 0, 0.25, 0.5, 0.75, respectively. Use Newton forward-difference formula and a forward difference table to construct interpolating polynomials of degree one, two and three. Approximate the function when the argument is 0.43 using each of the polynomials
The values of a function are 1, 1.64603, 3.61628, 4.94562 corresponding to the values of the argument 0, 0.25, 0.5, 0.75, respectively. Use Newton forward-difference formula and a forward difference table to construct interpolating polynomials of degree one, two and three. Approximate the function when the argument is 0.43 using each of the polynomials
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The values of a function are 1, 1.64603, 3.61628, 4.94562 corresponding to the values of
the argument 0, 0.25, 0.5, 0.75, respectively. Use Newton forward-difference formula and a forward
difference table to construct interpolating polynomials of degree one, two and three. Approximate
the function when the argument is 0.43 using each of the polynomials.
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