The value, V, of a Tiffany lamp, in dollars, t years after 1975 is given by V(t) = 225(1.15)t . Which of the following expressions is the average value of the lamp between 1975 and 2020? 45 + S 225(1.15)*dt 45 S 225(1.15)*dt V(0)+V(45) O None of the others are correct. O V(45)–V(0) 45 45 2 S 225(1.15)*dt

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

The value, \( V \), of a Tiffany lamp, in dollars, \( t \) years after 1975 is given by \( V(t) = 225(1.15)^t \). Which of the following expressions is the average value of the lamp between 1975 and 2020?

**Options:**

- Option A: 
  \[
  \frac{1}{45} \int_{0}^{45} 225(1.15)^t \, dt
  \]

- Option B: 
  \[
  \int_{0}^{45} 225(1.15)^t \, dt
  \]

- Option C: 
  \[
  \frac{V(0) + V(45)}{2}
  \]

- Option D: 
  None of the others are correct.

- Option E: 
  \[
  \frac{V(45) - V(0)}{45}
  \]

- Option F: 
  \[
  \frac{1}{2} \int_{0}^{45} 225(1.15)^t \, dt
  \]
Transcribed Image Text:**Problem Statement:** The value, \( V \), of a Tiffany lamp, in dollars, \( t \) years after 1975 is given by \( V(t) = 225(1.15)^t \). Which of the following expressions is the average value of the lamp between 1975 and 2020? **Options:** - Option A: \[ \frac{1}{45} \int_{0}^{45} 225(1.15)^t \, dt \] - Option B: \[ \int_{0}^{45} 225(1.15)^t \, dt \] - Option C: \[ \frac{V(0) + V(45)}{2} \] - Option D: None of the others are correct. - Option E: \[ \frac{V(45) - V(0)}{45} \] - Option F: \[ \frac{1}{2} \int_{0}^{45} 225(1.15)^t \, dt \]
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