The value of the equilibrium constant for the following reaction is 115. A + 2B ↔ 3C + D What is the value of the equilibrium constant for the reaction below? 2A + 4B ↔ 6C + 2D A. K = 115 B. K = (115)2 = 1.3 x 104 C. K = (115)1/2 = 10.7 D. K = (2 x 345)2 = 5.29 x 105 E. K = 2 x (345)2 = 2.64 x 105
The value of the equilibrium constant for the following reaction is 115. A + 2B ↔ 3C + D What is the value of the equilibrium constant for the reaction below? 2A + 4B ↔ 6C + 2D A. K = 115 B. K = (115)2 = 1.3 x 104 C. K = (115)1/2 = 10.7 D. K = (2 x 345)2 = 5.29 x 105 E. K = 2 x (345)2 = 2.64 x 105
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 47QRT
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The value of the equilibrium constant for the following reaction is 115.
A + 2B ↔ 3C + D
What is the value of the equilibrium constant for the reaction below?
2A + 4B ↔ 6C + 2D
A. K = 115
B. K = (115)2 = 1.3 x 104
C. K = (115)1/2 = 10.7
D. K = (2 x 345)2 = 5.29 x 105
E. K = 2 x (345)2 = 2.64 x 105
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