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The value of Lu(t-3)} is. B. e-(-+) A. e³ (-+) C. (++) D. e(++)

The value of Lu(t-3)} is. B. e-(-+) A. e³ (-+) C. (++) D. e(++)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1.-. e) The solution of = 5, y(0) = 1 is. A. x² = y² + 1 B. y² = x² + 1 2. ( A. 3.- 5. (. 8. A. y = c₁e² +₂e³ 4. - s) The general solution of r2y" + 3xy' + y = 0 is. A. y = ₁x + ₂x² B. y c₁x + c₂xln(x) 9. 10. s) The integrating factor of xy' + 3y = is. B. 2 C. 2³ A. 3 7. () The value of L{} is. A. e-t B. et 11. 3) The general solution of y" - 5y' +6y=0 is. B. y=c₁e²+ c₂e-32 C. 00 D. 3 6.- s) The minimum radius of convergence of power sreies solution about z = 1 of the ODE (x2 - 49)y" + 2xy' + y = 0.. B. 8 A. 7 A. 1 5) The radius of convergence of E(-1)*(-1) B. 0 8+3 The value of L-¹22) is. 82+28+1 B. 2tet + et A. 3tet + e-t The value of Lu(t-3)} is. B. e-(-+) A. e³a(+2) - C. y² = 2x² + 1 D. y² - x² = 0. The equivalent form of Using unit step functions is A. u(t-2) (sin(t)-3) +3 D. 3u(t-2) - sin(t)u(t-2) f(t) = C. y=c₁e-2z+c₂e³z C. y = 9+ln(z) The value of f sin(t)8(t-1)dt B. 0 C. 6 C. u(t) = { sin() C. 2te-t + e-t C. e³8 (++) 0<t<2 sin(t) t>2 B. 3u(t-2) + sin(t)u(t - 2) D. C. D. y cie-2 + c₂e-3z D. y=+ D. 5 D. 8(t) D. 3tet + et D. e38 (++) C. u(t-2) (sin(t) + 3) +3 D. √2
Transcribed Image Text:1.-. e) The solution of = 5, y(0) = 1 is. A. x² = y² + 1 B. y² = x² + 1 2. ( A. 3.- 5. (. 8. A. y = c₁e² +₂e³ 4. - s) The general solution of r2y" + 3xy' + y = 0 is. A. y = ₁x + ₂x² B. y c₁x + c₂xln(x) 9. 10. s) The integrating factor of xy' + 3y = is. B. 2 C. 2³ A. 3 7. () The value of L{} is. A. e-t B. et 11. 3) The general solution of y" - 5y' +6y=0 is. B. y=c₁e²+ c₂e-32 C. 00 D. 3 6.- s) The minimum radius of convergence of power sreies solution about z = 1 of the ODE (x2 - 49)y" + 2xy' + y = 0.. B. 8 A. 7 A. 1 5) The radius of convergence of E(-1)*(-1) B. 0 8+3 The value of L-¹22) is. 82+28+1 B. 2tet + et A. 3tet + e-t The value of Lu(t-3)} is. B. e-(-+) A. e³a(+2) - C. y² = 2x² + 1 D. y² - x² = 0. The equivalent form of Using unit step functions is A. u(t-2) (sin(t)-3) +3 D. 3u(t-2) - sin(t)u(t-2) f(t) = C. y=c₁e-2z+c₂e³z C. y = 9+ln(z) The value of f sin(t)8(t-1)dt B. 0 C. 6 C. u(t) = { sin() C. 2te-t + e-t C. e³8 (++) 0<t<2 sin(t) t>2 B. 3u(t-2) + sin(t)u(t - 2) D. C. D. y cie-2 + c₂e-3z D. y=+ D. 5 D. 8(t) D. 3tet + et D. e38 (++) C. u(t-2) (sin(t) + 3) +3 D. √2
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