The vacuum between cup and ceilling exerts no force on either. The atmospheric pressure of the air below the cup pushes up on it with a force (Patm)(A). If the cup barely supports the student's weight, then the normal force of the ceiling is approximately zero, and we have the following. E = 0 + (Patm)(A) – mg = 0 Solving for the area of the suction cup, we have mg A = atm 830.907 = 830.907

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Question
What must be the contact area between a suction cup (completely evacuated) and a ceiling if the cup is to
support the weight of an 84.7-kg student?
Part 1 of 3 - Conceptualize
As seen in the movies, the suction cups used by burglars to remove glass are about 10 cm in diameter, and it
seems reasonable that one of these might be able to support the weight of the student. The face area of a 10-
cm cup is approximately A = Tr² × 3(0.05 m)²x 0.008 m².
Part 2 of 3 - Categorize
Suction is not a new kind of force. Familiar forces hold the cup in equilibrium, one of which is the atmospheric
pressure acting over the area of the cup. This problem is another application of Newton's second law using the
particle-in-equilibrium model.
Part 3 of 3 - Analyze
The vacuum between cup and ceiling exerts no force on either. The atmospheric pressure of the air below the
cup pushes up on it with a force (P
atm)(A). If the cup barely supports the student's weight, then the normal
force of the ceiling is approximately zero, and we have the following.
EFy = 0 + (Patm)(A) – mg = 0
-
Solving for the area of the suction cup, we have
mg
A =
atm
830.907
= 830.907
Transcribed Image Text:What must be the contact area between a suction cup (completely evacuated) and a ceiling if the cup is to support the weight of an 84.7-kg student? Part 1 of 3 - Conceptualize As seen in the movies, the suction cups used by burglars to remove glass are about 10 cm in diameter, and it seems reasonable that one of these might be able to support the weight of the student. The face area of a 10- cm cup is approximately A = Tr² × 3(0.05 m)²x 0.008 m². Part 2 of 3 - Categorize Suction is not a new kind of force. Familiar forces hold the cup in equilibrium, one of which is the atmospheric pressure acting over the area of the cup. This problem is another application of Newton's second law using the particle-in-equilibrium model. Part 3 of 3 - Analyze The vacuum between cup and ceiling exerts no force on either. The atmospheric pressure of the air below the cup pushes up on it with a force (P atm)(A). If the cup barely supports the student's weight, then the normal force of the ceiling is approximately zero, and we have the following. EFy = 0 + (Patm)(A) – mg = 0 - Solving for the area of the suction cup, we have mg A = atm 830.907 = 830.907
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