The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 50 male consumers was $135.67, and the average expenditure in a sample survey of 38 female consumers was $68.64. Based on past surveys, the standard deviation for male consumers is assumed to be $35, and the standard deviation for female consumers is assumed to be $22. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)? At 99% confidence, what is the margin of error (to 2 decimals)? Develop a 99% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.

Q: newspaper reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A: Therefore, we are 99% confident that the true difference in average expenditures between male and…

Q: Round your answers to 2 decimal places. a. What is the point estimate of the difference between the…

A:

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A: Type II error = P( Fail to reject Ho| When mu = 25)

Q: The average expenditure on Valentine's Day was expected to be $100.89  (USA Today, February 13,…

A:

Q: A newspaper reports that the average expenditure on Valentine's Day is $100.89. De male and female…

A: The question is about confidence interval.Given :No. of male consumers ( n1 ) = 40No. of female…

Q: What

A: Explanation and solutions is given below....

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Q: What is the point estimate of the difference between the population mean expenditure for males and…

A: Provided data is, the average expenditure on Valentine's Day was expected to be $100.89. The average…

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Q: USA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do…

A: Given information:

Q: The average expenditure on Valentine's Day was expected to be $108.89 (USA Today, February 13,…

A: Given: Z value = 2.576 the standard deviation for male consumers is assumed to be $33 σ1=33 the…

Q: A newspaper reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A: given data male:x¯1  = 131.67σ1 = 45n1 = 40female:x¯2  = 69.64σ2 = 20n2 = 30claim : μ1 ≠ μ2

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Q: The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A:

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Q: USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A: Given data: Sample 1: Male Mean = $135.67  Standard deviation = $35 Sample size  = 40 Sample 2 :…

Q: USA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do…

A: Given information: x¯M=131.68nM=48σM=34x¯F=65.89nF=30σF=20z=2.576

Q: Suppose you know the population average wage in the manufacturing industry in the U.S. is $26.72 per…

A: true mean value = 25 mu = 26.72 s = 2.6

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Q: The average expenditure on Valentine's Day was expected to be $100.89  (USA Today, February 13,…

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Q: A newspaper reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

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Q: The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A: GivenFor male For female 1)The point estimate is calculated as shown below

Q: The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A: 1. The formula for the point estimate is: The point estimate for the true difference between the…

Q: reports that the average expenditure on Valentine's Day was expected to be $100.89. Do male and…

A: Given that    Sample sizes n1=60      , n2=37   Sample means X̄1=133.15   , X̄2= 60.72     ?1 =31…

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Q: (a) What is the point estimate (in dollars) of the difference between the population mean…

A: x1= 133.67x2 = 69.64   n1 = 40n2 = 30   s1 = 45s2 = 20

Q: USA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do…

A: Given Male consumers Sample size, n1=44 Sample mean, x¯1=$138.99 Pop sd, σ1=$33   Female consumer…

Q: You may need to use the appropriate appendix table or technology to answer this question. A…

A: Male consumer Sample size, n1=40 Sample mean, x¯1=132.67 Population sd, σ1=45   Female consumer…

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A: Given: Population mean expenditure, μ=100.89              Sample size for men, n1= 42…

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A: b. From part a. the point estimate is observed to be 67.03 and from part c. the 99% confidence…

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Q: USA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do…

A: Given: n1=46x¯1=130.6σ1=33n2=31x¯2=66.39σ2=20 CI = 99%=0.99

Q: The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female…

A: For male: The sample size, n1=40 The sample average expenditure (in $), x¯1=135.67. For female: The…

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