The United States Department of Agriculture (USDA) found that the proportion of young adults ages 20-39 who regu. skip eating breakfast is 0.238. Suppose that Lance, a nutritionist, surveys the dietary habits of a random sample of size n = 500 of young adults ages 20-39 in the United States. Apply the central limit theorem to find the probability that the number of individuals, X, in Lance's sample who regular skip breakfast is greater than 122. You may find table of critical values helpful. Express the result as a decimal precise to three places.

Q: A recent survey of 1090 U.S. adults selected at random showed that 621 consider the occupation of…

A: Given Information: The number of U.S adults (n) = 1090 The number of occupation of firefighters to…

Q: A survey showed that 75% of adults need correction for their eyesight. If 8 adults are randomly…

A: Given that 75% of adults need correction for their eyesight. There are 8 adults in the study. Let us…

Q: The National Sleep Foundation surveyed representative samples of adults in six different countries…

A: we have given that  n1=250 ,n2=250 ,xbar1=391 ,xbar2=426 ,s1=20 ,s2=44 alpha=0.05

Q: A traffic study has shown that the probability that 5 cars will pass over a small bridge in a…

A:

Q: The probability that the sample proportion surviving for at least 3 years will be less than 67% isO…

A: Given P=0.73 q=0.27 n=80

Q: About 70% of all female heart transplant patients will survive for at least 3 years. Sixty female…

A: From records: 70% of female heart transplant patients survive for at least 3 years.  Sample drawn =…

Q: A recent survey of 1050 U.S. adults selected at random showed that 625 consider the occupation of…

A: Out of 1050 randomly selected US adults, 625 consider the occupation of firefighter to to have very…

Q: The table summarizes results from 983 pedestrian deaths that were caused by automobile accidents.…

A: Total number of pedestrian who's no  intoxicated =70+573=643 Total number of accident=983 We want to…

Q: Suppose the life spans of a particular brand of car battery are normally distributed with a mean of…

A: We have given that  Mean=45.3

Q: The United States Department of Agriculture (USDA) found that the proportion of young adults ages…

A:

Q: A study showed that ​69.7% of occupants involved in a fatal car crash wore seat belts. Of those in a…

A:

Q: About 73​% of all female heart transplant patients will survive for at least 3 years. Ninety female…

A:

Q: The quality of computer disks is measured by the number of missing pulses. Fora certain brand of…

A: Binomial distribution: Consider a random experiment involving n independent trials, such that the…

Q: One half of the people in the United States own individual stocks. In a random sample of 12 people,…

A:

Q: A survey was conducted to determine the proportion of Grade 11 students who engage in under-age…

A: We have given that p = 0.70 n = 100 We have to calculate  P(x> 0.65)

Q: One manufacturer claims that only 10% of its total production is defective. 28 items are randomly…

A: Let, X=the number of defectives n=number of trial=28  p=probability of success=10%=0.10   X follows…

Q: For a particular diamond mine, 82% of the diamonds fail to qualify as gemstone grade. A random…

A: P=0.82n=102Probability of less than 88%fails to quality as genstonegrade is equivalent in Number as=…

Q: Suppose the scores, X, on a college entrance examination are normally distributed with a mean of…

A:

Q: uppose that 72% of Veterinary School graduates who take the licensure exam for their state pass the…

A: p =0.72 n = 150 z-critical value at 0.75 = 0.6745

Q: A recent survey of 1010 U.S. adults selected at random showed that 647 consider the occupation of…

A:

Q: A study conducted by the Center for Disease Control that asked 15,000 students about their sleep…

A:

Q: Let us suppose that some article modeled the disease progression in sepsis (a systemic inflammatory…

A:

Q: A pharmaceutical company is running trials on a new test for anabolic steroids. The company uses the…

A: To find the relative frequency of a false negative result (probability that an athlete using…

Q: The data in the following table show the association between cigar smoking and death from cancer for…

A: Given data is   Died from cancer Did Not Die from cancer Total Never smoked cigars 805 118334…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.