The uniform bar has a mass m (given below) and length L (given below). It is released from rest at an angle 0 as shown. The moment of inertia of the rod about the pin point O is Io =;mL². Neglect friction at 0. a) Determine the radius of gyration of the rod about the mass center G. b) Draw the free-body diagram of the rod at the instant shown.

Q: Figure E1.28 y B (15.0 m) Ď (10.0 m) 30.0° 53.0° 25.0° Č (12.0 m) (Ả (8.00 m) f. Solve for A xC • D.

A: Given, From mentioned in question, all vectors are in xy plane, (no mention about z axis) Magnitude,…

Q: Two streams merge to form a river. One stream has a width of 8.3 m, depth of 3.3 m, and current…

A:

Q: b) For the figure below If X1= 0.3m, X2 0.75m, X3= 1.06m, X4 = 1.4m, and Y= 1.75m, Y2= 1.70m, Y3 =…

A:

Q: The work required to lift eleven 94.0 lb bags of cement from the ground to the bed of a truck is…

A:

Q: In the following diagram, d=10m 30 O a. Fx=8.66m, Fy=-5m O b. Fx=-8.66m, Fy=-5m O c. Fx=-8.66m,…

A: in the following diagram, we have to find the X-coordinate of force i.e. Fx and X-coordinate of…

Q: A 3123kg car is going up the Amerat hill, at angle 15.3, with 3 people inside the car each of 74kg.…

A:

Q: 11. Find e (in degrees). (0.35m, 0.49m) Knee Ankle (0.1m, 0.15m)

A: GivenCoordinates of Ankle (x1,y1) = (0.1 m, 0.15 m)Coordinates of Knee (x2,y2) = (0.35 m, 0.49 m)

Q: .0 x 10^3 dyne.dm/score to horsepower

A:

Q: v, (m/s) 12.0 F 8.00 4.00 1 (s) 2.00 4.00 6.00 8.00 10.0 12.0

A: The area enclosed by a velocity vs time graph represents the displacement of the object.

Q: 64 lb/cm3 to kg/m3

A: Given: The given value is 64 lb/cm3.

Q: 2kQ V = Vx2 + a²

A:

Q: Convert 10^3 g x L^-1 to kg x m^-3

A: Answer  103 gL-1=103 kg m-3

Q: If  A=3ĵ, A⨯B=12î, and A·B=27, find B.

A: Given:A=3ĵA⨯B=12îA·B=27

Q: 2.5 x 10² m² j. 5.00 m

A:

Q: A swimmer swims 10 complete laps in a pool . It takes 15secs to complete the swim . The pool is 30m…

A:

Q: If a sphere has a volume of 375.6cm^3, what is the diameter in dm and feet?

A: Volume of the sphere is given asV= volume of the spherer=radius of the sphere

Q: 3.00 m 6.00 m (B

A:

Q: Kgft g.m Convert 280 into min

A: Given data:  280 Kg.ft/min Required: Value in g.m/s

Q: Given Xo = Om X= 5.30m Vo V= Om/s ( rest) ニ to = Os 七= 5、59s

A: Given : xo = 0 m x = 5.30 m v = 0 m/s to = 0s t = 5.59 s

Q: 2100kg cm2/m3 day =? lbm yd2 /ft3 hr

A: 1 kg = 2.205 lb 1 cm = 0.010936 yd 1 m = 3.2808 ft  1 day = 24 hours

Q: Calculate  r=3.81 *10^8 m -(6.371x10^6m

A:

Q: A rectangular box is h = 15 inches in high, w = 26.5 cm wide, and L = 0.15 yards long. v=

A:

Q: Problem 3: A 500-kg dragster accelerates from rest to a final speed of 110 m/sec in 400 m (about a…

A:

Q: 6. The volume of a cube is 250 mm3. What is the length of one of the sides?

A:

Q: Block A is placed on the horizontal surface while block B is on the inclned one. The blocks are…

A: Free body diagram for block B is shown below,

Q: Given A=38yi tYxyj+z² and B= xzi+yaj+zK Find die (A.B).

A: Given: A→=3x2yi^+4xyj^+z2k^B→=xzi^+yzj^+z2k^

Q: A 2000kg car traveling at 21 m/s takes 51m to stop under full braking. The same car under similair…

A: Given : m = 2000 kg vo = 21 m/s s = 51 m v = 0 (because finally the car stops) To determine :…

Q: Problem #2 R-150 Lbs Length FR- 15 feet Length FE- S fet Calculate E Calculate MA

A: GIVEN: Here, R (Weight or LOAD) = 150 Lbs Converting pounds (lbs) to kilogram (kg), we get R = 68.04…

Q: 150kg=quintal

A:

Q: n correctly calodates the length in kilometers and orientation in degrees west of south of km

A: Given: A=4.4 Km θc=24o B=2.48 Km C=3.02 Km

Q: Find t= sqrt (2s/g) Given s = -93.00 ± 3.00 , g = -9.8 (take this as an exact number). t…

A: Given Data:Displacement Acceleration due to gravity Formula for time to be used To Determine:The…

Q: Calculate a · b when a = 2i – 3j + 5k, b=i+2j + 8k

A:

Q: angular acceleration

A:

Q: A projectile is modelled by the function 9.81 t + vot + ho, 2 h(t) with h measured in meters. Using…

A:

Q: y 4 m y = 4 16 -8 m Consider the area in . 9:49 am ✔

A:

Q: 28. Which of the following corresponds to the equation B + T = S А. В. T. T. C. D. T

A: Required:  The sum of two vectors B and T The resultant vector is S

Q: A=26kg B = 25kg =310 dg =? %3D A 310 2skg B.

A:

Q: l.67 Ka info ma 3.296X10 Km into mm.

A: Step 1: Part (2) 1 kg=106 mg8.76 kg=8.76 kg×106 mg1 kg8.76 kg=8.76×106 mg Thus, there are 8.76X106…

Q: 132 x 1.62m/s'

A: