The uncertainty in an electron’s position is 0.010 nm. (a) What is the minimum uncertainty ∆p in its momentum? (b) What is the kinetic energy of an electron whose momentum is equal to this uncertainty (∆p = p)?

We are given uncertainty in position of electron. We have to find uncertainty in momentum for this electron. We then find the kinetic energy of electron whose momentum is equal to this uncertainty.

The Heisenberg uncertainty principle is given as

$∆x∆p\ge \frac{h}{4\pi }$

Here $∆x,∆p$ are uncertainty in position and momentum respectively. 

The minimum uncertainty is given as

$∆x∆p=\frac{h}{4\pi }$