The tyrue density of solid material in an activated alumina particle as 3.675 g/cc. the density of the particle determined by mercury displacement is 1.547. the surface area by adsorption measurement is 175 m2/g. from this information compute the pore volume per gram, the porosity of the particle ,and the mean pore radius.the bulk density of a bed of the alumina particle in a 250 cm3 graduate is 0.81 g/cm3. what fraction of the total volume of the bed is void space between the particle and what fraction is void space within the particle
The tyrue density of solid material in an activated alumina particle as 3.675 g/cc. the density of the particle determined by mercury displacement is 1.547. the surface area by adsorption measurement is 175 m2/g. from this information compute the pore volume per gram, the porosity of the particle ,and the mean pore radius.the bulk density of a bed of the alumina particle in a 250 cm3 graduate is 0.81 g/cm3. what fraction of the total volume of the bed is void space between the particle and what fraction is void space within the particle
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The tyrue density of solid material in an activated alumina particle as 3.675 g/cc. the density of the particle determined by mercury displacement is 1.547. the surface area by adsorption measurement is 175 m2/g. from this information compute the pore volume per gram, the porosity of the particle ,and the mean pore radius.the bulk density of a bed of the alumina particle in a 250 cm3 graduate is 0.81 g/cm3. what fraction of the total volume of the bed is void space between the particle and what fraction is void space within the particle
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