The two loads shown in (Figure 1) can be described as follows: Load 1 absorbs an average power of 60 kW and delivers 70 kVAR of reactive power; Load 2 has an impedance of (24+57) 2. The voltage at the terminals of the loads is 2200/2 cos 120mt V. Figure 0,05 Ω j05 Ω www 0,05 Ω 10.5 Ω www V₁L₁ 1 of 1 L₂ Part A Find the rms value of the source voltage. Enter your answer in volts to three significant figures using polar notation. Express argument in degrees. V₂= 19Η ΑΣΦ.Η. vec 6 Submit Request Answer Part B Complete previous part(s) Part C Complete previous part(s) Provide Feedback ? V (rms)

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The two loads shown in (Figure 1) can be described as follows:
Load 1 absorbs an average power of 60 kW and delivers
70 kVAR of reactive power; Load 2 has an impedance of
(24+7) S2. The voltage at the terminals of the loads is
2200√2 cos 120πt V.
Figure
0,05 Ω 10.5 Ω
www
0,05 Ωj0.5 Ω
ww
+
V₁L₁
<
1 of 1 >
4₂
Part A
Find the rms value of the source voltage.
Enter your answer in volts to three significant figures using polar notation. Express argument in degrees.
V
Vg²
Submit
-- ΑΣΦ
VO AΣ vec
Request Answer
Part B Complete previous part(s)
Part C Complete previous part(s)
Provide Feedback
?
V (rms)
Transcribed Image Text:The two loads shown in (Figure 1) can be described as follows: Load 1 absorbs an average power of 60 kW and delivers 70 kVAR of reactive power; Load 2 has an impedance of (24+7) S2. The voltage at the terminals of the loads is 2200√2 cos 120πt V. Figure 0,05 Ω 10.5 Ω www 0,05 Ωj0.5 Ω ww + V₁L₁ < 1 of 1 > 4₂ Part A Find the rms value of the source voltage. Enter your answer in volts to three significant figures using polar notation. Express argument in degrees. V Vg² Submit -- ΑΣΦ VO AΣ vec Request Answer Part B Complete previous part(s) Part C Complete previous part(s) Provide Feedback ? V (rms)
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