The two intervals (114.9, 115.3) and (114.6, 115.6) are confidence intervals (calculated using the same sample data) for μ = true average resonance frequency (in hertz) for all tennis racketsof a certain type.(a) What is the value (in hertz) of the sample mean resonance frequency? (Hint: Where is the confidence interval centered?)hertz(b) The confidence level for one of these intervals is 90% and for the other it is 99%. Which one has a confidence level of 99%?O (114.9, 115.3)O (114.6, 115.6)O It is impossible to tell which is which.How can you tell?O The 99% confidence interval should be wider than the 90% confidence interval.The center of the 99% confidence interval should be less than the center of the 90% confidence interval.O The center of the 99% confidence interval should be greater than the center of the 90% confidence interval.O The 99% confidence interval should be narrower than the 90% confidence interval.O It is impossible to tell which is which.

Two Interval (114.9,115.3) and (114.6,115.6)

Answered: The two intervals (114.9, 115.3) and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The following information is obtained for a sample of 80 observations taken from a population. SS xx 370.842, se = 0.922, and y = 164.43 - 2.83x Make a 97 % confidence interval for B. = Round your answers to two decimal places. The 97 % confidence interval for Bis ( i ).
Question 9 A student was asked to find a 95% confidence interval for widget width using data from a random sample of size n = 18. Which of the following is a correct interpretation of the interval 12 <µ < 34.8? Check all that are correct. O With 95% confidence, the mean width of a randomly selected widget will be between 12 and 34.8. With 95% confidence, the mean width of all widgets is between 12 and 34.8. O The mean width of all widgets is between 12 and 34.8, 95% of the time. We know this is true because the mean of our sample is between 12 and 34.8. O There is a 95% chance that the mean of the population is between 12 and 34.8. O There is a 95% chance that the mean of a sample of 18 widgets will be between 12 and 34.8. Question Help: DPost to forum Submit Question FEB átv
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Answer question 7 and 8
Question 3 The following questions are based on confidence intervals. iid Ν μ, σ") with μER (a) and o? is unknown. Calculate a 90% confidence interval for u. Let, (4.00, 5.26, 4.84, 6.77, 5.23, 5.64, 3.84, 6.4,3 3.35, 4.28) (b) Interpret the the confidence interval in (a).
Question 8 A researcher must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 22.6 59.2 40.9 17.3 64.2 |35.6 Assuming the population of temperatures are normally distributed, find the 80% confidence interval. Round the answers to two decimal places. Enter your answer as an interval of the form (LB,UP). The researcher is 80% confident that the population average temperature is within the temperature interval Question Help: DVideo Submit Question 1jpg
2. Each of the following is a confidence interval for µ = true average (i.e., population mean) resonance frequency (Hz) for all tennis rackets of a certain type: (114.4, 115.6) (114.1, 115.9) a. What is the value of the sample mean resonance frequency? b. Both intervals were calculated from the same sample data. The confidence level for one of these intervals is 90% and for the other is 99%. Which of the intervals has the 90% confidence level, and why?
Question 12 Astudent was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Which of the following is a correct interpretation of the interval 0.13 p < 0.27? Check all that are correct. With 90% confidence, the proportion of all students who take notes is between 0.13 and0.27. U There is a 90% chance that the proportion of the population is between 0.13 and 0.27. O There is a 90% chance that the proportion of notetakers in a sample of 86 students wilL be between 0.13 and 0.27. O The proprtion of all students who take notes is between 0.13 and 0.27, 90% of the time. OWith 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.13 and 0.27.
Two confidence intervals, (119.4 Hz, 120.6 Hz) and (119.1 Hz, 120.9 Hz), are constructed for the mean resonance frequency (in Hz) for all tennis rackets of a certain type using the same sample data. Which interval represents the higher level of confidence? 9.
Find the confidence interval for a Related-Samples t-test (Ch.11), given the following info: Level of confidence = 99% Before and After scores = see table below SSD (SS of the difference scores) = 2.75 Hint: as you’re doing calculations, don’t round any numbers in your calculations to less than two decimal places, or your final answer may be too rounded for you to be able to tell which answer below is correct. Person Before X1 After X2 Difference (D = X2- X1) A 15 22 +7 B 18 23 +5 C 12 17 +5 D 17 23 +6 A. 1.90 < μD < 7.18 B. 2.53 < μD < 8.02 C. 2.95 < μD < 8.55 D. 2.01 < μD < 7.58
How many adults should be involved in this study in order to have the mean age estimated up to ±6 months with 92% and 98% confidence levels?
5

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