**Description:****Figure Details:**- The diagram displays two positive charges separated by a distance \(d = 3.00 \, \text{cm}\).- The charge on the left is labeled \(Q = +2.00 \, \text{nC}\).- The charge on the right is labeled \(2Q\), indicating it is double the charge of \(Q\), thus \(+4.00 \, \text{nC}\).- Points A and B are located directly above \(Q\) and \(2Q\) respectively, forming a square with sides labeled \(d\).**Tasks:****(a) Find the electric potential at point A.**- A text box is provided for input.- An error message indicates: "Your response differs from the correct answer by more than 100%."**(b) Find the electric potential at point B.**- A text box labeled with "kV" is provided for input.**(c) Find the electric potential difference between B and A.**- A text box labeled with "V" is provided for input.**Instructions:**Determine the electric potentials at points A and B due to the nearby charges using the formula for electric potential:\[ V = \frac{kQ}{r} \]where \( V \) is the electric potential, \( k \) is Coulomb’s constant \((8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2)\), \( Q \) is the charge, and \( r \) is the distance from the charge.Calculate the potential difference as the potential at B minus the potential at A:\[ \Delta V = V_B - V_A \]

The electric potential at any point P be defined as, VP=kQr Where, k be defined as the Coulomb…

The two charges in the figure below are separated by a distance d = 3.00 cm, and Q = +2.00 nC. В d. d 20 O (a) Find the electric potential at A. Your response differs from the correct answer by more than 100%. kV (b) Find the electric potential at B. kV (c) Find the electric potential difference between B and A. V

The two charges in the figure below are separated by a distance d = 3.00 cm, and Q = +2.00 nC. В d. d 20 O (a) Find the electric potential at A. Your response differs from the correct answer by more than 100%. kV (b) Find the electric potential at B. kV (c) Find the electric potential difference between B and A. V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

**Description:**

**Figure Details:**
- The diagram displays two positive charges separated by a distance \(d = 3.00 \, \text{cm}\).
- The charge on the left is labeled \(Q = +2.00 \, \text{nC}\).
- The charge on the right is labeled \(2Q\), indicating it is double the charge of \(Q\), thus \(+4.00 \, \text{nC}\).
- Points A and B are located directly above \(Q\) and \(2Q\) respectively, forming a square with sides labeled \(d\).

**Tasks:**

**(a) Find the electric potential at point A.**
- A text box is provided for input.
- An error message indicates: "Your response differs from the correct answer by more than 100%."

**(b) Find the electric potential at point B.**
- A text box labeled with "kV" is provided for input.

**(c) Find the electric potential difference between B and A.**
- A text box labeled with "V" is provided for input.

**Instructions:**
Determine the electric potentials at points A and B due to the nearby charges using the formula for electric potential:

\[ V = \frac{kQ}{r} \]

where \( V \) is the electric potential, \( k \) is Coulomb’s constant \((8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2)\), \( Q \) is the charge, and \( r \) is the distance from the charge.

Calculate the potential difference as the potential at B minus the potential at A:

\[ \Delta V = V_B - V_A \]

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