The two-by-two table below shows the results for a case control study with 40 cases and 80 controls. Exposed Unexposed Total Cases 25 15 40 Controls 10 70 80 Total 35 85 120 Using the 2x2 table above, a chi-square test was used to test the association between disease and exposure. The resulting p-value was 0.001. Which of the following best interprets the result? Question 5 options: Based on a chi-square test with 2 degrees of freedom, we find that there is a statistically significant association between disease and exposure (p=0.001). Based on a chi-square test with 2 degrees of freedom, we find that there is a weak association between disease and exposure (p=0.001). Based on a chi-square test with 1 degrees of freedom, we find that there is a weak association between disease and exposure (p=0.001). The results should not be interpreted because a Fisher's exact test should have been used instead. Based on a chi-square test with 1 degrees of freedom, we find that there is a statistically significant association between disease and exposure (p=0.001).

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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The two-by-two table below shows the results for a case control study with 40 cases and 80 controls.

 

 

 

 

Exposed

Unexposed

Total

                Cases

25

15

40

                Controls

10

70

80

                Total

35

85

120

 

Using the 2x2 table above, a chi-square test was used to test the association between disease and exposure. The resulting p-value was 0.001. Which of the following best interprets the result?

 

Question 5 options:

 

Based on a chi-square test with 2 degrees of freedom, we find that there is a statistically significant association between disease and exposure (p=0.001).

 

Based on a chi-square test with 2 degrees of freedom, we find that there is a weak association between disease and exposure (p=0.001).

 

Based on a chi-square test with 1 degrees of freedom, we find that there is a weak association between disease and exposure (p=0.001).

 

The results should not be interpreted because a Fisher's exact test should have been used instead.

 

Based on a chi-square test with 1 degrees of freedom, we find that there is a statistically significant association between disease and exposure (p=0.001).

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