Homework Help is Here – Start Your Trial Now!
Engineering
Mechanical Engineering
The two blocks A and B have weights WA= 79 lb and WB = 12 lb. (Figure 1) If the kinetic coefficient of friction between the incline and block A is μk = 0.2, determine the speed of A after it moves 3 ft down the plane starting from rest. Neglect the mass of the cord and pulleys

The two blocks A and B have weights WA= 79 lb and WB = 12 lb. (Figure 1) If the kinetic coefficient of friction between the incline and block A is μk = 0.2, determine the speed of A after it moves 3 ft down the plane starting from rest. Neglect the mass of the cord and pulleys

International Edition---engineering Mechanics: Statics, 4th Edition
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter9: Moments And Products Of Inertia Of Areas
Section: Chapter Questions
Problem 9.46P
See similar textbooks
icon
Related questions
Question
100%

The two blocks A and B have weights WA= 79 lb and WB = 12 lb.
(Figure 1)

If the kinetic coefficient of friction between the incline and block A is μk = 0.2, determine the speed of A after it moves 3 ft down the plane starting from rest. Neglect the mass of the cord and pulleys.
Express your answer to three significant figures and include the appropriate units.
 
View Available Hint(s)for Part A
Hint 1for Part A. How to approach the problem
Use the principle of work and energy for the system of two blocks, which states that the system's initial kinetic energy plus the work done by all the forces acting on the two blocks as they move from their initial to their final position is equal to the system's final kinetic energy. Each block moves with its own speed, and to solve this problem, you need to find the relationship between these speeds.
Hint 2for Part A. The relationship between the speeds of the blocks
Write the equation that relates the blocks’ displacements, sAsA and sBsB, with the length of the cord. Differentiating this equation, you can express the speed of block BB, vBvB, in terms of the speed of block AA, vAvA.
 
The answer is not 6.07 ft/s. You may have omitted the work done by the friction force in your calculations. Recall that the friction force does negative work.
 
5 4 3.
Transcribed Image Text:5 4 3.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Forced Undamped Vibrations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
International Edition---engineering Mechanics: St…
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L
Principles of Heat Transfer (Activate Learning wi…
Principles of Heat Transfer (Activate Learning wi…
Mechanical Engineering
ISBN:
9781305387102
Author:
Kreith, Frank; Manglik, Raj M.
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS