The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules per unit time by a enzyme molecule. The concentration of enzyme active sites is not necessarily equal to the concentration of enzyme molecules, because some enzyme molecules have more than one active site. If the enzyme molecule has one active site, the turnover number is given by turnover number == =k₂ (Rmax is often written as Vmax) Rmax [E] If the enzyme molecule has more than one active site, then [E], is multiplied by the number of active sites to determine its effective concentration. Determine the value of the turnover number of the enzyme carbonic anhydrase, given that Rmax for carbonic anhydrase equals 249 μmol-Ls and [E], = 2.25 nmol L. Carbonic anhydrase has a single active site. turnover number = 8-1
The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules per unit time by a enzyme molecule. The concentration of enzyme active sites is not necessarily equal to the concentration of enzyme molecules, because some enzyme molecules have more than one active site. If the enzyme molecule has one active site, the turnover number is given by turnover number == =k₂ (Rmax is often written as Vmax) Rmax [E] If the enzyme molecule has more than one active site, then [E], is multiplied by the number of active sites to determine its effective concentration. Determine the value of the turnover number of the enzyme carbonic anhydrase, given that Rmax for carbonic anhydrase equals 249 μmol-Ls and [E], = 2.25 nmol L. Carbonic anhydrase has a single active site. turnover number = 8-1
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules
per unit time by al enzyme molecule. The concentration of enzyme active sites is not necessarily equal to the concentration of
enzyme molecules, because some enzyme molecules have more than one active site. If the enzyme molecule has one active site,
the turnover number is given by
turnover number =
Rmax
[E],
=k₂ (Rmax is often written as Vmax)
If the enzyme molecule has more than one active site, then [E], is multiplied by the number of active sites to determine its
effective concentration.
turnover number =
Determine the value of the turnover number of the enzyme carbonic anhydrase, given that Rmax for carbonic anhydrase equals
249 μmol-L¹s¹ and [E], = 2.25 nmol L. Carbonic anhydrase has a single active site.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1f10484-52a0-4233-b031-0df053dd075b%2Fc1e9e90a-e87c-48b4-aa7e-7fb0cacb2196%2Fic45l8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules
per unit time by al enzyme molecule. The concentration of enzyme active sites is not necessarily equal to the concentration of
enzyme molecules, because some enzyme molecules have more than one active site. If the enzyme molecule has one active site,
the turnover number is given by
turnover number =
Rmax
[E],
=k₂ (Rmax is often written as Vmax)
If the enzyme molecule has more than one active site, then [E], is multiplied by the number of active sites to determine its
effective concentration.
turnover number =
Determine the value of the turnover number of the enzyme carbonic anhydrase, given that Rmax for carbonic anhydrase equals
249 μmol-L¹s¹ and [E], = 2.25 nmol L. Carbonic anhydrase has a single active site.
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