The turd is launched at a speed of 47 m/s at an angle of 39 degrees above the horizontal. At exactly what time after launch should the ground be covered in a portal to intercept the turd before it hits the ground?
The turd is launched at a speed of 47 m/s at an angle of 39 degrees above the horizontal. At exactly what time after launch should the ground be covered in a portal to intercept the turd before it hits the ground?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem: Projectile Motion**
A projectile is launched at a speed of 47 m/s at an angle of 39 degrees above the horizontal. Determine the exact time after launch when a portal should cover the ground to intercept the projectile before it hits the ground.
**Concepts Involved:**
1. **Initial Velocity (u):** 47 m/s
2. **Angle of Projection (θ):** 39 degrees
3. **Horizontal and Vertical Components of Velocity:**
- Horizontal velocity (u_x) = u * cos(θ)
- Vertical velocity (u_y) = u * sin(θ)
4. **Time of Flight (t):** Use the formula for the time of flight of a projectile:
\[
t = \frac{2u_y}{g}
\]
where \(g = 9.81 \, \text{m/s}^2\) (acceleration due to gravity)
**Objective:**
Calculate the time of flight to determine when the ground should be covered in a portal to intercept the projectile.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e0e1a50-ba3f-4042-a2ac-5820bcfd7374%2F712a23ad-75b2-4d9a-bf41-2f3f115d92c6%2Fv8wdxf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem: Projectile Motion**
A projectile is launched at a speed of 47 m/s at an angle of 39 degrees above the horizontal. Determine the exact time after launch when a portal should cover the ground to intercept the projectile before it hits the ground.
**Concepts Involved:**
1. **Initial Velocity (u):** 47 m/s
2. **Angle of Projection (θ):** 39 degrees
3. **Horizontal and Vertical Components of Velocity:**
- Horizontal velocity (u_x) = u * cos(θ)
- Vertical velocity (u_y) = u * sin(θ)
4. **Time of Flight (t):** Use the formula for the time of flight of a projectile:
\[
t = \frac{2u_y}{g}
\]
where \(g = 9.81 \, \text{m/s}^2\) (acceleration due to gravity)
**Objective:**
Calculate the time of flight to determine when the ground should be covered in a portal to intercept the projectile.
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