The truss shown is part of a roof system supporting the following service loads: Roof live load = 750 Pa of horizontal projection of the roof surface Purlin weight = 175 Pa of roof surface Roofing materials = 725 Pa of roof surface Wind load = 1,400 Pa perpendicular to roof surface Trusses are spaced at 6 m on centers and sag rods are used at midspan between trusses. Spacing of purlins is 0.7 m on centers. Use A36 steel (F,= 250 MPa and Fu= 400 MPa). Total allowable deflection is L/240 where L is the length between supports. Consider only loads perpendicular to the strong axis in computing for the actual deflection. Consider moment, shear and deflection. For loading combinations refer to NSCP 2015. Use LRFD

Structural Analysis
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Chapter2: Loads On Structures
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The truss shown is part of a roof system
supporting the following service loads:
= 750 Pa of
Roof live load
horizontal projection of the roof surface
Purlin weight
= 175 Pa of roof
surface
Roofing materials = 725 Pa of roof
surface
Wind load
= 1,400 Pa
perpendicular to roof surface
Trusses are spaced at 6 m on centers and sag
rods are used at midspan between trusses.
Spacing of purlins is 0.7 m on centers. Use A36
steel (Fy= 250 MPa and Fu= 400 MPa). Total
allowable deflection is L/240 where L is the length
between supports. Consider only loads
perpendicular to the strong axis in computing for
the actual deflection. Consider moment, shear
and deflection. For loading combinations refer to
NSCP 2015. Use LRFD
Tgagrod
Purlin
3,5m
15m
Determine the factored uniform load (KN/m)
normal to the x-axis.0
Transcribed Image Text:The truss shown is part of a roof system supporting the following service loads: = 750 Pa of Roof live load horizontal projection of the roof surface Purlin weight = 175 Pa of roof surface Roofing materials = 725 Pa of roof surface Wind load = 1,400 Pa perpendicular to roof surface Trusses are spaced at 6 m on centers and sag rods are used at midspan between trusses. Spacing of purlins is 0.7 m on centers. Use A36 steel (Fy= 250 MPa and Fu= 400 MPa). Total allowable deflection is L/240 where L is the length between supports. Consider only loads perpendicular to the strong axis in computing for the actual deflection. Consider moment, shear and deflection. For loading combinations refer to NSCP 2015. Use LRFD Tgagrod Purlin 3,5m 15m Determine the factored uniform load (KN/m) normal to the x-axis.0
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