the true statement. a) Ammeter is an instrument used to measure potential difference across any element in a circuit b) Voltmeter is an instrument used to measure current in a circuit c) Galvanometer constant is dimensionless d) Current sensitivity is expressed as the exact reverse of the galvanometer constant
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the true statement.
a) Ammeter is an instrument used to measure potential difference across any element in a circuit
b) Voltmeter is an instrument used to measure current in a circuit
c) Galvanometer constant is dimensionless
d) Current sensitivity is expressed as the exact reverse of the galvanometer constant
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- 2) The circuit shown contains the following three resistors wired to a 6 V battery: R₁ = 652 R₂ = 852 R3 = 492 a) Calculate the equivalent resistance of the circuit. (2) b) Calculate the voltage across R3. (2) www R₁ Page 2 R₂ R3I. RESISTANCE IN A CIRCUIT Construct a circuit using a schematic diagram with at least 6 resistors connected in combination of series and parallel connection then compute for the total resistance in the circuit.10 identical capacitors of C=1 F are arranged in series in an electric circuit. What is the equivalent capacitance? 10 F 0.1 F O It depends on the electric current 1 F O It depends on the voltage of the battery
- 3. Find the readings of the ammeter and voltmeter in the circuits in Figure 3. The resistance of the voltmeter is Ry = 1 200 Q, the voltage at the battery is U = 80 V, the resistances R1= 300 Q and R2 = 480 N. Disregard the resistance of the battery and the ammeter. R1 Figure 3.If the resistance of a conductor is doubled, the current gets halved. This is because: A) I = V - R B) I = V/R C) I = Rn/V D) I = VR2) Find the equivalent resistance and the total current in the circuit, if the voltage is 110 V. RA R23 7.00 15.0 n 21.0 n. R1 13.0 N
- Q7. Calculate the equivalent resistance of the circuit below. R1 = 20 Q R2 = 15 Q R3 = 8 0 R4 = 15 2 R3 = 20 2The voltage drop from a to b is 82 V. a) Calculate the equivalent resistance of the circuit b) How much current is flowing through R1? c)How much current is flowing through R5? d)How much current is flowing through R2? e) What is the voltage across R4?a) Find the equivalent resistance of the illustrated circuit. b) Using Ohm's law, determine the current and potential difference in each of the resistors. At the end, make a table with all the results. c) Determine the power dissipated by the 12 Ω resistor.
- 2 A physics teacher has just demonstrated how a certain component in a circuit can cause the electrical current to decrease over time. Which of the following values shows this measurement in the correct SI base units?1. In the laboratory of Resistances in Series and in Parallel the circuit of Figure 1 was studied, the resistance and voltage values recorded were R 1 = 13 2, R 2 = 14 n, R 3 = 30 Y V = 6 v. in R1 I, I, V R2 I123 3 R3 Figure 1: Series circuit with three resistors. a) Calculate the voltage across the resistor R 1: b) Calculate the equivalent resistance R 123 : Note: Enter your answer WITHOUT units, for example if your answer is 1.23453 N enter 1.23453 c) Calculate the current I 123 : ww_______________1. Is the law that governs the relationship among current, voltage, and resistance in an electric circuit._______________2. Defined as the quantity of charge passing through a given point per unit time. _______________3. Is the flow of positive charges from the positive terminal of the battery to the negative._______________4. Opposition of certain material to the flow of current._______________5. The SI unit of current is ______._______________6. Is a circuit where current flows in one direction._______________7. Is a circuit that contains more than one electrical component connected one after the other in a single path._______________8. When the current flowing through the circuit constantly changes direction and magnitude, the circuit is called _______._______________9. A type of circuit where the current flowing across the system is constant. _______________10. A type of circuit where the equivalent voltage across the system is equal to the voltage drop of each load