PROBLEM 2.18The trajectory of an object is given by the equation x(t) = (5m) + (26m/s)t –(12m/s² )t²22. For which time t is the displacement x(t) at its maximum?2.083sb.c. 4.083 sd. 1.083 sа.3.082s23. What is this maximum value?c. 20.08 md. 21.08 mа.18.08 mb.19.08 m

Answered: Image /qna-images/answer/a5db1b78-6d4d-4e25-8eeb-1da5e52b02ce.jpg

Answered: The trajectory of an object is given by…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A some instant in time a rocket experiences an acceleration due to gravity and thrust from the rocket engine of: and has a velocity of: ā= 5.657î -3.843ĵ m/s² v = 5000 + 2000 m/s. Determine: i) the acceleration due to the rocket engine; ii) a, and an; iii) the radius of curvature of the trajectory at this instant ANS. at = 3.825 m/s^2, an = 5.669 m/s^2, p=5,115,541 m
A police car is traveling at a velocity of 20.0 m/s due north, when a car zooms by at a constant velocity of 47.0 m/s due north. After a reaction time 0.800 s the policeman begins to pursue the speeder with an acceleration of 3.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder? Number i Units Vos A VOS North AVP AVOP AVOP Police car catches up with speeder ↑ ap Police car begins to accelerate - Speeder passes police car
A car travels along a path described as y = p and an when x = 2 m and x = 6 m. Round all answers to three (3) significant digits When = = 2m: P₁ = 15.8 an = 5.13 When x = 6 m: P2 = 84.4 an = 0.96 x m X m x m X m 2² ²+2 and has a constant velocity of v = 9 8 m What is the
a particle travels along a straight line with a velocity v=(12-3t^2) m/s, where t is in seconds. when t=1s, the particle is located 10m to the left of the origin. A) Determine the displacement, in meters, from t=0 to t=10s B) determine the acceleration, in m/s^2, when t=4s C) Determine the distance the particle travels, in meters, from t=0 to t=10s
+51 suspension You are an engineer designing the suspension of an ATV. You want to ensure that the vehicle doesn't "bottom out" even when landing from being airborne. An approximation describing the vertical acceleration of the suspension upon impact is I a(s) 9.8(1 12s) m/s² where the initial velocity at impact is v=1.5 m/s with the spring initially uncompressed, s = 0 m A) What is the vertical velocity of the ATV chassis after the spring is compressed 0.1 m? B) What is the maximum distance the spring gets compressed? (This occurs when the ATV's vertical motion comes momentarily to rest)

Recommended textbooks for you

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Control Systems Engineering

Mechanical Engineering

ISBN:

9781118170519

Author:

Norman S. Nise

Publisher:

WILEY

Mechanics of Materials (MindTap Course List)

Mechanical Engineering

ISBN:

9781337093347

Author:

Barry J. Goodno, James M. Gere

Publisher:

Cengage Learning

Engineering Mechanics: Statics

Mechanical Engineering

ISBN:

9781118807330

Author:

James L. Meriam, L. G. Kraige, J. N. Bolton

Publisher:

WILEY

SEE MORE TEXTBOOKS

The trajectory of an object is given by the equation x(t) = (5m) + (26m/s)t – (12m/s² )t² 22. For which time t is the displacement x(t) at its maximum? %3D c. 4.083 s d. 1.083 s а. 2.083s b. 3.082s 23. What is this maximum value? 18.08 m 19.08 m c. 20.08 m d. 21.08 m а. b.