The trajectory of an arrow traveling in Earth's gravity without air resistance is shown below at points a through e. The arrow has initial speed vo and is launched at angle to the horizontal. The vertical dashed lines represent equal time interval, At. (Note: g = 9.81 m/s²) y(m) Vo Ө 00 a b At point b the vertical velocity is: O Vo sin (0) + ½ g (24t)2 O Vo cos (0) + ½ g (24t)2 Vo cos (0)-g (24t) O Vo sin (0)-g (24t) e x(m)

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The trajectory of an arrow traveling in Earth's gravity without air resistance is shown below at points a
through e. The arrow has initial speed vo and is launched at angle to the horizontal. The vertical dashed
lines represent equal time interval, At.
(Note: g = 9.81 m/s²)
y(m)
Vo
a
b
At point b the vertical velocity is:
Vo sin (0) + ½ g (24t)2
O Vo cos (0) + ½ g (24t)2
O 0
C
O Vo cos (0)-g (24t)
O Vo sin (0)-g (2At)
d
x(m)
Transcribed Image Text:The trajectory of an arrow traveling in Earth's gravity without air resistance is shown below at points a through e. The arrow has initial speed vo and is launched at angle to the horizontal. The vertical dashed lines represent equal time interval, At. (Note: g = 9.81 m/s²) y(m) Vo a b At point b the vertical velocity is: Vo sin (0) + ½ g (24t)2 O Vo cos (0) + ½ g (24t)2 O 0 C O Vo cos (0)-g (24t) O Vo sin (0)-g (2At) d x(m)
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