The traditional method of analysis for the amount of chloride ion present in a sample is to dissolve the sample in water and then slowly to add a solution of silver nitrate. Silver chloride is very insoluble in water, and by adding a slight excess of silver nitrate, it is possible to effectively remove all chloride ion from the sample. Ag*(aq) + Cl" (aq) AgCI(s) Suppose a 2.066-g sample is known to contain 14.9% chloride ion by mass. a. What mass of silver nitrate must be used to completely precipitate the chloride ion from the sample? b. What mas of silver chloride will be obtained? Molar Mass: Ag: 107.87 g/mol N: 14.01 g/mol O: 16 g/mol Cl: 35.45 g/mol Round off your answers to 2 decimal places.

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The traditional method of analysis for the amount of chloride ion present in a sample is to dissolve the sample in water and then slowly to add a solution of silver nitrate.
Silver chloride is very insoluble in water, and by adding a slight excess of silver nitrate, it is possible to effectively remove all chloride ion from the sample.
Ag*(aq) + Cl" (aq)→ AgCl(s)
Suppose a 2.066-g sample is known to contain 14.9% chloride ion by mass.
a. What mass of silver nitrate must be used to completely precipitate the chloride ion from the sample?
b. What mass of silver chloride will be obtained?
Molar Mass:
Ag: 107.87 g/mol
N: 14.01 g/mol
O: 16 g/mol
Cl: 35.45 g/mol
Round off your answers to 2 decimal places.
Transcribed Image Text:The traditional method of analysis for the amount of chloride ion present in a sample is to dissolve the sample in water and then slowly to add a solution of silver nitrate. Silver chloride is very insoluble in water, and by adding a slight excess of silver nitrate, it is possible to effectively remove all chloride ion from the sample. Ag*(aq) + Cl" (aq)→ AgCl(s) Suppose a 2.066-g sample is known to contain 14.9% chloride ion by mass. a. What mass of silver nitrate must be used to completely precipitate the chloride ion from the sample? b. What mass of silver chloride will be obtained? Molar Mass: Ag: 107.87 g/mol N: 14.01 g/mol O: 16 g/mol Cl: 35.45 g/mol Round off your answers to 2 decimal places.
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