(the trace of A). Prove that T is a linear transformation. Let A and B be to matrices in M, and let the entries of A, B be denoted a, and b;, respectively, for 1 i,jsn. By matrix addition, 'n, we know that the entries of the matrix A + B are of the form aj + bị and associative property of addition, we have which of the fol ---Select--- ai · bj v for 1 si, j s n. By the definition of T and the commutative T(A + B) = (a, ·b,) + -… + %3D aj + bị ("q ."e) - = (a, + ... + a,) + (b, + .… + = T(A) + T(B) hq . he aj + bj T(A + B) = (a, + b;)· + ... + (a, + b,) ai + b = (a, + ... + a,) + (b1 = T(A) + T(B) T(A + B) = (a11 + b11) - + (ann bo) = (a,1 + ** + ann) + (b,1 + + bon) = T(A) + T(B) T(A + B) = (a11 b11) + … + (ann :bn) = (a,, + … + ann) + (b,1 + . + bon) = T(A) + T(B) Now, let c be a scalar. By scalar multiplication, we know that the entries of the matrix CA are of the form + aj v, 1si,jsn. By the definition of T and the distributive property of multiplication, we have which of the following? T(CA) = ca, + ** + ca, = c(a, + ... + a,) = cT(A) T(CA) = ca11 + ... + ca n = c(a,, + . + a = cT(A) T(CA) = ca, ca, = c(a, + ... + a) = cT(A) T(CA) = ca1 · can = c(a11 = CT(A) + ... + a nn)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Define T: M, n
- R by
T(A) = a11 + a22
(the trace of A). Prove that T is a linear transformation.
Let A and B be to matrices in M, er and let the entries of A, B be denoted a, and b, respectively, for 1 < i,jsn. By matrix addition,
v for 1 <i, j < n. By the definition of T and the commutative
...
we know that the entries of the matrix A + B are of the form aij + bji
and associative property of addition, we have which of the fol ---Select---
ai · bj
aij + bji
(a, · b,) + ... + (a, b,)
= (a, + .. + a,) + (b, + . + b,)
= T(A) + T(B)
T(A + B) =
lq . he
aij · bij
aij + bij
ai + b
T(A + B) = (a, + b,) + …· + (a, + b,)
= (a, + ... + a,) + (b, +
= T(A) + T(B)
+ b,)
+ bon)
(a11 + b11)
= (a,, + .. +
= T(A) + T(B)
T(A + B) =
+ .. + (aan
ann) + (b11
... + bon)
T(A + B) = (a,11 · b11) + … + (ann: bon)
= (a1 + … + apn) + (b,1 + .… + bon)
= T(A) + T(B)
Now, let c be a scalar. By scalar multiplication, we know that the entries of the matrix CA are of the form + aj
v, 1s i, js n.
By the definition of T and the distributive property of multiplication, we have which of the following?
T(CA) = ca,
+ ... + ca n
= c(a, + .. + a)
= cT(A)
T(CA) = ca, 1+… + ca pn
= c(a11
= cT(A)
+ ... + apn)
T(CA) = ca, can
= c(a, + ... + a)
= cT(A)
T(CA) = ca1' cann
= c(a11
+ ... + ann)
= CT(A)
Transcribed Image Text:Define T: M, n - R by T(A) = a11 + a22 (the trace of A). Prove that T is a linear transformation. Let A and B be to matrices in M, er and let the entries of A, B be denoted a, and b, respectively, for 1 < i,jsn. By matrix addition, v for 1 <i, j < n. By the definition of T and the commutative ... we know that the entries of the matrix A + B are of the form aij + bji and associative property of addition, we have which of the fol ---Select--- ai · bj aij + bji (a, · b,) + ... + (a, b,) = (a, + .. + a,) + (b, + . + b,) = T(A) + T(B) T(A + B) = lq . he aij · bij aij + bij ai + b T(A + B) = (a, + b,) + …· + (a, + b,) = (a, + ... + a,) + (b, + = T(A) + T(B) + b,) + bon) (a11 + b11) = (a,, + .. + = T(A) + T(B) T(A + B) = + .. + (aan ann) + (b11 ... + bon) T(A + B) = (a,11 · b11) + … + (ann: bon) = (a1 + … + apn) + (b,1 + .… + bon) = T(A) + T(B) Now, let c be a scalar. By scalar multiplication, we know that the entries of the matrix CA are of the form + aj v, 1s i, js n. By the definition of T and the distributive property of multiplication, we have which of the following? T(CA) = ca, + ... + ca n = c(a, + .. + a) = cT(A) T(CA) = ca, 1+… + ca pn = c(a11 = cT(A) + ... + apn) T(CA) = ca, can = c(a, + ... + a) = cT(A) T(CA) = ca1' cann = c(a11 + ... + ann) = CT(A)
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