Calculate the total clear sky irradiation of a surface tilted at an angle of 60° from the horizontal located atCaribou, ME, on July 21 at 2:00 P.M. solar time. The latitude for the given location is 68.02° N. The surfacefaces the southwest. Neglect reflected radiation. Use Gae = CGND Fws for diffuse solar radiation.Answer: G, = 252 Btu/hr-ft', Gae = 26.58 Btu/hr-ft', Total irradiation = 278.58 Btu/hr-ft%3D

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the total clear sky irradiation of a surface tilted at an angle of 60° from the horizontal located at ME, on July 21 at 2:00 P.M. solar time. The latitude for the given location is 68.02° N. The surface outhwest. Neglect reflected radiation. Use Gae = CGND Fws for diffuse solar radiation. o = 252 Btu/hr-ft", Gae = 26.58 Btu/hr-ft", Total irradiation = 278.58 Btu/hr-ft

the total clear sky irradiation of a surface tilted at an angle of 60° from the horizontal located at ME, on July 21 at 2:00 P.M. solar time. The latitude for the given location is 68.02° N. The surface outhwest. Neglect reflected radiation. Use Gae = CGND Fws for diffuse solar radiation. o = 252 Btu/hr-ft", Gae = 26.58 Btu/hr-ft", Total irradiation = 278.58 Btu/hr-ft

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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