The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 17 minutes and a standard deviation of 2 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit? Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) The percent of customers that receive the service for half-price is%. (Round to two decimal places as needed.) (b) The guaranteed time limit isminutes. (Round up to the nearest minute.)
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 17 minutes and a standard deviation of 2 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit? Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) The percent of customers that receive the service for half-price is%. (Round to two decimal places as needed.) (b) The guaranteed time limit isminutes. (Round up to the nearest minute.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Transcribed Image Text:The time required for an automotive center to complete an oil change service on an automobile approximately
follows a normal distribution, with a mean of 17 minutes and a standard deviation of 2 minutes.
(a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does
take longer, the customer will receive the service for half-price. What percent of customers receive the service
for half-price?
(b) If the automotive center does not want to give the discount to more than 3% of its customers, how long
should it make the guaranteed time limit?
Click here to view the standard normal distribution table (page 1).
Click here to view the standard normal distribution table (page 2).
(a) The percent of customers that receive the service for half-price is%.
(Round to two decimal places as needed.)
(b) The guaranteed time limit is minutes.
(Round up to the nearest minute.)
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