The time it takes a pizza delivery driver to reach his destination for a sample of 28 deliveries has a mean of 36 minutes. The standard deviation of those 28 deliveries is s = 2 minutes. Construct an 85% confidence interval to estimate the true mean of all his pizza deliveries. (35.440,36.560) (27.520,28.480) (35.259,36.741) (27.347,28.653)

A random sample of 41 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.09 years, with sample standard deviation s = 0.88 years. However, it is thought that the overall population mean age of coyotes is ? = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use ? = 0.01. (a) State the null and alternate hypotheses.(Select the correct one) H0: ? = 1.75 yr; H1: ? ≠ 1.75 yr H0: ? > 1.75 yr; H1: ? = 1.75 yr     H0: ? = 1.75 yr; H1: ? > 1.75 yr H0: ? = 1.75 yr; H1: ? < 1.75 yr (b) What is the value of the sample test statistic? Round your answer to three decimal places.     (c) Estimate the P-value.     (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level ??(Selet which one is correct) We fail to reject the null hypothesis because the p-value is greater than ? = 0.01.…

The length of human pregnancies from conception to birth is known to be normally distributed with a mean of 266 days and standard deviation of 16 days. A pregnancy longer than "nine months" might be considered as 274 days or longer (four months have 30 days, and February has 28 in most years). What proportion of pregnancies last more than "9 months?" First, find the z-score for 274: (274 -266)/16 0.5. Then, find the area to the of 0.5, using the table. Your answer Need help on this question? Read the ebook page on this topic (1no penaltyi Geta hint (fewer pelnte Show answer (nopoint

A sample is selected from a population with = 150. After a treatment is administered to the individuals, the sample mean is found to be = 140 and the standard deviation is S= 9. If the sample has n = 18 scores, determine whether the sample is sufficient to conclude that the treatment has significant effect. Use a two tail test with = 0.02.