The time (in minutes) a postal clerk spends with his or her customer is known to have an exponential distribution with the average amount of time being 6 minutes. a. The lambda of this distribution is The probability that the time is longer than 9 is P(x 2 9) =| c. The probability that the time is shorter than 4 is P(x s 4) = d. The probability that the time is between 3 and 7 is P(3 s x s 7) = b. e. The 73rd percentile is a phone call that lasts minutes.

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The time (in minutes) a postal clerk spends with his or her customer is known to have an
exponential distribution with the average amount of time being 6 minutes.
a. The lambda of this distribution is
b. The probability that the time is longer than 9 is P(x 2 9) =
c. The probability that the time is shorter than 4 is P(x s 4) =|
d. The probability that the time is between 3 and 7 is P(3 s x s 7) =
e. The 73rd percentile is a phone call that lasts
minutes.
Transcribed Image Text:The time (in minutes) a postal clerk spends with his or her customer is known to have an exponential distribution with the average amount of time being 6 minutes. a. The lambda of this distribution is b. The probability that the time is longer than 9 is P(x 2 9) = c. The probability that the time is shorter than 4 is P(x s 4) =| d. The probability that the time is between 3 and 7 is P(3 s x s 7) = e. The 73rd percentile is a phone call that lasts minutes.
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a) Let us assume x=the time a postal clerk spends with his or her customerx follows an exponential distribution with average amount of time=6So, 1λ=6or, λ=16=0.166666666667

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