The tide depth in Deep Cove, British Columbia, from 4:00 to 15:00 on January 6, 2011, can be modelled accurately by the polynomial function: f(t) = 0.001t³0.055t² + 0.845t +0.293 where f(t) is the tide depth in metres and t is the number of hours after midnight. a) What is the tide depth at 14:00 on January 6 (to the nearest tenth of a metre)?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2. The tide depth in Deep Cove, British Columbia, from 4:00 to 15:00 on January 6, 2011, can be
modelled accurately by the polynomial function:
f(t) = 0.001t ³-0.055t² + 0.845t + 0.293
where f(t) is the tide depth in metres and t is the number of hours after midnight.
a) What is the tide depth at 14:00 on January 6 (to the nearest tenth of a metre)?
b) When is the tide depth the greatest on January 6?
c) What are the restrictions on the variable t? Does this match the domain of the function?
d) How would you use this data to determine the tide depth on January 7, 2011?
Transcribed Image Text:2. The tide depth in Deep Cove, British Columbia, from 4:00 to 15:00 on January 6, 2011, can be modelled accurately by the polynomial function: f(t) = 0.001t ³-0.055t² + 0.845t + 0.293 where f(t) is the tide depth in metres and t is the number of hours after midnight. a) What is the tide depth at 14:00 on January 6 (to the nearest tenth of a metre)? b) When is the tide depth the greatest on January 6? c) What are the restrictions on the variable t? Does this match the domain of the function? d) How would you use this data to determine the tide depth on January 7, 2011?
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