The three series An, EBn, and Cn have terms 1 An = n8 1 Bn 1 C, = n4 ' n Use the Limit Comparison Test to compare the following series to any of the above series. For each of the series below, you must enter two letters. The first is the letter (A,B, or C) of the series above that it can be legally compared to with the Limit Comparison Test. The second is C if the given series converges, or D if it diverges. So for instance, if you believe the series converges and can be compared with series C above, you would enter CC; or if you believe it diverges and can be compared with series A, you would enter AD. 5n2 + 5n7 1. 4n8 + 7n3 – 4 n=1 4n4 +n8 1496n12 + 7n4 +5 5n5 + n? – 5n n- 3. 7n13 – 5n10 +8 n=1
The three series An, EBn, and Cn have terms 1 An = n8 1 Bn 1 C, = n4 ' n Use the Limit Comparison Test to compare the following series to any of the above series. For each of the series below, you must enter two letters. The first is the letter (A,B, or C) of the series above that it can be legally compared to with the Limit Comparison Test. The second is C if the given series converges, or D if it diverges. So for instance, if you believe the series converges and can be compared with series C above, you would enter CC; or if you believe it diverges and can be compared with series A, you would enter AD. 5n2 + 5n7 1. 4n8 + 7n3 – 4 n=1 4n4 +n8 1496n12 + 7n4 +5 5n5 + n? – 5n n- 3. 7n13 – 5n10 +8 n=1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The three series An, Bn, and Cn have terms
1
1
1
a C, =
An
B,
n8 »
n
Use the Limit Comparison Test to compare the following series to any of the above series. For each of the series below, you must enter two letters. The first is
the letter (A,B, or C) of the series above that it can be legally compared to with the Limit Comparison Test. The second is C if the given series converges, or D if
it diverges. So for instance, if you believe the series converges and can be compared with series C above, you would enter CC; or if you believe it diverges and
can be compared with series A, you would enter AD.
5n2 + 5n7
1.
4n8 + 7n3 – 4
n=
4n4 +n8
2. E
1496n12 + 7m4 + 5
n=1
5n5 + n2 – 5n
-
3.
7n13 – 5n10 +8
n=1
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