the third Taylor polynomial for f(x) = expanded abc= 3(x)=7-7(x-1)-14(x-1)²-7(x-1)³ 3(x)-7-7(x-1)+7(x-1)²-7(x-1)³ 3(x)-7-7(x-1) + 14(x-1)²-14(x-1)³ 3(x) = 7-7(x+1)+7(x + 1)²-7(x+1)³

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A: Given the polynomialf(x)=x3+4x2+5x+2

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A: Topic = Functions

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A: The value of X1=∆y3=y4-y3=24-17⇒X1=7and value of ∆2y2=X2=∆y3-∆y2=7-3=4⇒X2=4

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A: As per our guidelines we can answer only 1 question so kindly repost the remaining questions…

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Q: 2b. Please

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