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The Thévenin equivalent circuit is derived from the Norton equivalent circuit as shown below. Given IN = 5 A, RN = 39 2, calculate the value of the Thévenin equivalent resistance Rth in ohms to one decimal place.

The Thévenin equivalent circuit is derived from the Norton equivalent circuit as shown below. Given IN = 5 A, RN = 39 2, calculate the value of the Thévenin equivalent resistance Rth in ohms to one decimal place.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Title: Calculating Thévenin Equivalent Resistance from a Norton Equivalent Circuit** --- **Introduction:** The process of deriving a Thévenin equivalent circuit from a Norton equivalent circuit is an essential concept in electrical engineering. It aids in simplifying complex circuits for easier analysis. **Problem Statement:** Given the Norton equivalent circuit parameters: - Norton current, \( I_N = 5 \, \text{A} \) - Norton resistance, \( R_N = 39 \, \Omega \) Calculate the Thévenin equivalent resistance \( R_{Th} \) in ohms accurate to one decimal place. **Circuit Explanation:** *Diagram Description*: 1. **Norton Equivalent Circuit:** - A current source \( I_N \) of 5 A is depicted on the left. - The current source is in parallel with a resistor \( R_N \) of 39 Ω. - Two nodes are marked as a and b, defining the points for which the equivalent is to be found. 2. **Thévenin Equivalent Circuit:** - On the right, the circuit reduces to a voltage source \( V_{Th} \) in series with a resistor \( R_{Th} \), connected between the same nodes a and b. **Solution:** Since \( R_{Th} = R_N \) for conversion purposes (Thévenin and Norton resistances are equal), the Thévenin equivalent resistance \( R_{Th} \) is: \[ R_{Th} = 39.0 \, \Omega \] This simplified calculation helps in further analysis or integration of the circuit into larger systems. --- **Conclusion:** By understanding these conversions, engineers can model electrical networks with greater flexibility and accuracy, enhancing problem-solving efficiency.
Transcribed Image Text:**Title: Calculating Thévenin Equivalent Resistance from a Norton Equivalent Circuit** --- **Introduction:** The process of deriving a Thévenin equivalent circuit from a Norton equivalent circuit is an essential concept in electrical engineering. It aids in simplifying complex circuits for easier analysis. **Problem Statement:** Given the Norton equivalent circuit parameters: - Norton current, \( I_N = 5 \, \text{A} \) - Norton resistance, \( R_N = 39 \, \Omega \) Calculate the Thévenin equivalent resistance \( R_{Th} \) in ohms accurate to one decimal place. **Circuit Explanation:** *Diagram Description*: 1. **Norton Equivalent Circuit:** - A current source \( I_N \) of 5 A is depicted on the left. - The current source is in parallel with a resistor \( R_N \) of 39 Ω. - Two nodes are marked as a and b, defining the points for which the equivalent is to be found. 2. **Thévenin Equivalent Circuit:** - On the right, the circuit reduces to a voltage source \( V_{Th} \) in series with a resistor \( R_{Th} \), connected between the same nodes a and b. **Solution:** Since \( R_{Th} = R_N \) for conversion purposes (Thévenin and Norton resistances are equal), the Thévenin equivalent resistance \( R_{Th} \) is: \[ R_{Th} = 39.0 \, \Omega \] This simplified calculation helps in further analysis or integration of the circuit into larger systems. --- **Conclusion:** By understanding these conversions, engineers can model electrical networks with greater flexibility and accuracy, enhancing problem-solving efficiency.
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