The tetraethyl lead [Pb(C2H5)4] in a 25-mL sample of aviation gasoline was shaken with 15.00 mL of 0.02095M l2. The reaction is Pb(C2H5)4 + I2 = Pb(C2H5)3I + C2H5I After the reaction was complete, the unused I2 was titrated with 6.09 mL of 0.03465 M sodium thiosulfate. Calculate the weight (in mg) of tetraethyl lead (MW = 323.4) in each liter of gasoline
The tetraethyl lead [Pb(C2H5)4] in a 25-mL sample of aviation gasoline was shaken with 15.00 mL of 0.02095M l2. The reaction is Pb(C2H5)4 + I2 = Pb(C2H5)3I + C2H5I After the reaction was complete, the unused I2 was titrated with 6.09 mL of 0.03465 M sodium thiosulfate. Calculate the weight (in mg) of tetraethyl lead (MW = 323.4) in each liter of gasoline
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The tetraethyl lead [Pb(C2H5)4] in a 25-mL sample of aviation gasoline was shaken
with 15.00 mL of 0.02095M l2. The reaction is
Pb(C2H5)4 + I2 = Pb(C2H5)3I + C2H5I
After the reaction was complete, the unused I2 was titrated with 6.09 mL of
0.03465 M sodium thiosulfate. Calculate the weight (in mg) of tetraethyl lead (MW
= 323.4) in each liter of gasoline
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VIEWStep 3: Finding out the No.of moles of I2 left unreacted with tetraethyl lead
VIEWStep 4: Number of moles of tetraethyl lead in 25mL
VIEWStep 5: weight of tetraethyl lead in 1liter gasoline
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