The testing times for a group of college students were normally distributed with a mean of μ = 33 minutesand a standard deviation of o 2 minutes.The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equalto the standard deviation.Fill in the indicated boxes.μ-30 μ-20 μ-μ-o μ μ+o μ+20 μ+30Used the Empirical Rule to complete the following statements:68% of testing times were between 31 o minutes and95% of testing times were betweenμ = 33σ=299.7% of testing times were between50% of testing times were belowminutes andminutes andminutes.minutes.minutes.minutes.

given data normal distributionμ = 33σ = 2 empirical rule : approximately 68-95-99.7% data fall…

Answered: The testing times for a group of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.7 parts/million (ppm). A researcher believes that the current ozone level is not at the normal level. The mean of 13 samples is 4.9 ppm with a standard deviation of 1.0. Does the data support the claim at the 0.1 level? Assume the population distribution is approximately normal. Step 3 of 3: Make the decision to reject or fail to reject the null hypothesis.
The following is a frequency distribution of ages of residents of a senior citizens' home in New York. Fill in the midpoints, then calculate the mean and the standard deviation. Round to two decimal positions. You may assume the data represents a population. Ages of Residents Midpoints Frequency 54−6254-62 3 63−7163-71 4 72−8072-80 1 81−8981-89 2 Mean (μμ)= Standard deviation (σσ) = Round the standard deviation up to 2 decimal places if necessary. Hint: Use the midpoint for each class (ages of residents).
For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 39 beats per minute, the mean of the listed pulse rates is x = 78.0 beats per minute, and their standard deviation is s = 13.1 beats per minute. %3D a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 39 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between - 2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 39 beats per minute significant? a. The difference is beats per minute. (Type an integer or a decimal. Do not round.)
Rachael got a 660 on the analytical portion of the Graduate Record Exam (GRE). If GRE scores are normally distributed and have mean μ = 600 and standard deviation σ = 30, what is her standardized score?
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ=$1.502 and standard deviation σ=$1.031.
Assume the birth weights at a local hospital have a normal distribution with a mean of 110 oz and a standard deviation of 15 oz. Draw a normal curve and label the mean and each value which is one, two, or three standard deviations above the mean. Then label each value which is one, two, or three standard deviations below the mean.
Oil field studies have shown that permeability measurements are having a normal distribution with a mean of 68 µD and a standard deviation of 10 µD. Determine the permeability that is exceeded by 90% of the samples. Select one: O a. 80.9 O b.55.1 C. 80.8 O d. 55.2
The testing times for a group of college students were normally distributed with a mean of u : 31 minutes and a standard deviation of o = 4.8 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes. H = 31 4.8 O = H-30 u-20 u - o μ+ 20 μ+3σ Used the Empirical Rule to complete the following statements: 68% of testing times were between minutes and minutes. 95% of testing times were between minutes and utes. 99.7% of testing times were between minutes and minutes. 50% of testing times were below minutes.
Given the following mean and standard deviation, find the z-score for each individual score. Find the difference between the data value and the mean then divide by the standard deviation. X = 10 a. X= 8 s = 2 Z = %3D b. X= 38 X = 40 s = 5 Z = С. X%3D94 X = 100 s = 10 z = d. X= 65 X = 50 s = 10 Z = %3D e. X= 30 X = 25 s = 5 Z =
The weights of six-week-old poults (juvenile turkeys) are normally distributed with mean u = 9.1 pounds and standard deviation o = 2.4 pounds. Find the 20n percentile of the weights. Use Table A.2 as needed. Round your final answer to the nearest tenth. Do not round intermediate computations.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P70, the 70-percentile. This is the temperature reading separating the bottom 70% from the top 30%.P70 = °C
The teacher in a kindergarten school measures the height of her students. If the heights were normally distributed with the mean of 112 cm and a standard deviation 3.25 cm, find the heights x that corresponds to the following z-scores: z = 2.24 z = -1.52 z = 0.76

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