The terminal side of an angle 0 in standard position passes through the point (-3,-4). Use the figure to find the following value. cos 8 cos = (Type an exact answer in simplified form. Rationalize all denominators.) G a

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
Question
**Trigonometry Practice Problem**

---

**Problem Statement:**

The terminal side of an angle θ in standard position passes through the point (-3, -4). Use the figure to find the following value.

\[ \cos \theta \]

**Figure Explanation:**

The figure accompanying the problem shows a coordinate plane with both the x-axis and y-axis labeled. An angle θ is depicted in standard position with its terminal side intersecting the point (-3, -4). The figure includes a right triangle with legs of length 3 and 4 units, corresponding to the x and y coordinates respectively. The hypotenuse is implied by the diagram and forms the side opposite to the angle θ, originating from the origin (0,0) and passing through the point (-3, -4).

**Calculation:**

Find \( \cos \theta \) using the coordinates of the point and the Pythagorean theorem.

\[ \cos \theta = \frac{\text{adjacent side}}{\text{hypotenuse}} = \frac{x}{r} \]

Where:
- \( x \) is -3 (the adjacent side, projection on the x-axis),
- \( r \) is the hypotenuse.

First, calculate the hypotenuse (\( r \)) using the Pythagorean theorem:

\[ r = \sqrt{x^2 + y^2} = \sqrt{(-3)^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \]

Then, 

\[ \cos \theta = \frac{-3}{5} \]

\[ \cos \theta = -\frac{3}{5} \]

---

**Answer Box:**

\[ \cos \theta = -\frac{3}{5} \]

(Type an exact answer in simplified form. Rationalize all denominators.)

---

This trigonometric problem helps to understand how to determine the cosine of an angle given its coordinates in a standard position on the coordinate plane. By using the figure and the relationships in a right triangle, students apply the Pythagorean theorem and trigonometric definitions to find the exact value.
Transcribed Image Text:**Trigonometry Practice Problem** --- **Problem Statement:** The terminal side of an angle θ in standard position passes through the point (-3, -4). Use the figure to find the following value. \[ \cos \theta \] **Figure Explanation:** The figure accompanying the problem shows a coordinate plane with both the x-axis and y-axis labeled. An angle θ is depicted in standard position with its terminal side intersecting the point (-3, -4). The figure includes a right triangle with legs of length 3 and 4 units, corresponding to the x and y coordinates respectively. The hypotenuse is implied by the diagram and forms the side opposite to the angle θ, originating from the origin (0,0) and passing through the point (-3, -4). **Calculation:** Find \( \cos \theta \) using the coordinates of the point and the Pythagorean theorem. \[ \cos \theta = \frac{\text{adjacent side}}{\text{hypotenuse}} = \frac{x}{r} \] Where: - \( x \) is -3 (the adjacent side, projection on the x-axis), - \( r \) is the hypotenuse. First, calculate the hypotenuse (\( r \)) using the Pythagorean theorem: \[ r = \sqrt{x^2 + y^2} = \sqrt{(-3)^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] Then, \[ \cos \theta = \frac{-3}{5} \] \[ \cos \theta = -\frac{3}{5} \] --- **Answer Box:** \[ \cos \theta = -\frac{3}{5} \] (Type an exact answer in simplified form. Rationalize all denominators.) --- This trigonometric problem helps to understand how to determine the cosine of an angle given its coordinates in a standard position on the coordinate plane. By using the figure and the relationships in a right triangle, students apply the Pythagorean theorem and trigonometric definitions to find the exact value.
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