I need the answer as soon as possible Not yThe temperature of a cold orange with an average mass ofMarke0.348 kg and average specific heat of 3.42 kJ/kg-K rises fromP Flac7.7°C to 29.4°C as a result of heat transfer from thesurrounding air. The entropy change of the orange isO a. 0.2547 kJ/KO b. 1.5945 kJ/KO c. 0.0920 kJ/KO d. 0.0886 kJ/KO e. 4.5820 kJ/K

The temperature of a cold orange with an average mass of 0.348 kg and average specific heat of 3.42 kJ/kg-K rises from 7.7°C to 29.4°C as a result of heat transfer from the surrounding air. The entropy change of the orange is a. 0.2547 kJ/K O b. 1.5945 kJ/K O c. 0.0920 kJ/K O d. 0.0886 kJ/K O e. 4.5820 kJ/K

The temperature of a cold orange with an average mass of 0.348 kg and average specific heat of 3.42 kJ/kg-K rises from 7.7°C to 29.4°C as a result of heat transfer from the surrounding air. The entropy change of the orange is a. 0.2547 kJ/K O b. 1.5945 kJ/K O c. 0.0920 kJ/K O d. 0.0886 kJ/K O e. 4.5820 kJ/K

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Suppose a hippopotamus on land receives 73 units of heat per minute due to solar radiation and 52 units of heat per minute due to infrared radiation. It emits 39 units of infrared radiation and it loses 66 units heat per minute through evaporation. The hippopotamus gains 45 units of heat per minute through its metabolism. Overall, its heat energy is increasing by 50 units per minute (i.e. its temperature is increasing). Delta Hanimal = SR + IRin - IRout ± Hconv ± Hcond - Hevap + Hmet Based on this information we can conclude that the combination of conduction and convection is the animal, and that its current temperature is than the ambient temperature. Select one: a. cooling; warmer b. warming; warmer c. cooling; cooler d. warming; cooler
Help me please
Show your complete solution.
An electric hot water heater consumes 3.1 kilowatts of electricity and converts it to heat. How long will it take the water heater to heat a 67 gallon tank of water from 10 degrees Celsius to 50 degrees Celsius? (1 kilogram of water is 0.37 gallons, 1 Calorie = 4200 J). It may be helpful to refer back to the weekly handout for guidance on this problem. Your final answer should be in minutes (rounded to the nearest 10 minutes).
can you please provide the solution for the answer in Reaction Ay?
Q. Define : Mechanical efficiency.
When does force work?
Illustrate the reciprocating action of piston inside the cylinder taking into consideration for suction and delivery of liquid from lower level to higher level, with neat diagram.
What’s the correct answer please?
The solution (298.349) is incorrect as well.
13. The amount of heat (Hth, thermal energy) stored in rocks, m = 500 kg, S = 840 J/(kg °C), Tfinal =50°C, Tinitial = 40°C is: ·Hth = 19*10E(6) Joules. ·Hth = 4.2 * 10E(6) Joules. %3D ·Hth = 4.2*10E(4)Joules. %3D
Describe processes occur in a certain direction, and not in the reverse direction.