The Taylor polynomial of degree 100 for the function fabout x = 3 is given by P (x) = (x – 3)² – (2–3)4 (x–3)® (x–3)100 n+1 (x-3)²" +(-1)"+1 n! + %3| + +.... ... 2! 3! 50! What is the value of f(24) (3)? 1 24! 24! 12! 1 24! 24! 12! 1 12!

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