Answered: The tangents for a D = 4º30' circular…

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Question

The tangents for a D = 4º30' circular curve (arc definition) meet at PI Sta 34+18.19 and the deflection angle I = 25º48'.

1) Compute L, T, E, M, LC, R for circular curves .

2) Calculate the Stations of the PC and PT, plus the total chords and deflection angles for all the full stations on the curve.

Station
Defl Increment (ö)
Defl Angle (Eö)
Total Chord (Cpc)
PT=
PC =

Expert Solution

Step 1

$\begin{array}{rcl} D & = & 4^{o} 30; \\ P I S t a 34 + 18.19 \\ ∆ & = & 25^{o} 48' \\ R & = & 12' \\ L & = & \frac{πR ∆}{180} \\ = & 5.405 f t \\ T & = & R \tan (\frac{∆}{2}) \\ = & 12 \tan (\frac{25^{o} 48'}{2}) \\ = & 2.75 f t \\ E & = & R (\frac{1}{\cos (\frac{∆}{2})} - 1) \\ E & = & 0.311 f t \\ M & = & R (1 - \cos (\frac{∆}{2})) \\ M & = & 0.303 f t \\ S t a t i o n P C & = & P I - T \\ = & 3418.19 - 2.75 \\ = & 3415.44 f t \\ S t a t i o n P T & = & P C + L \\ = & 3415.44 + 5.405 \\ = & 3420.845 f t \\ \frac{d c}{f t} & = & \frac{∆}{2 l} = \frac{25^{o} 48'}{5 \times 5.405} \\ = & 2.386 f t \end{array}$

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