The tangent plane at a point Po (f(uovo) 9 (uovo).h (uo.vo)) on a parametrized surface r(u,v) = f(u,v) i + g(u,v) j+h(u,v) k is the plane through Po normal to the vector ru (uovo) xrv (uo,vo), the cross product of the tangent vectors ru (40.vo) and rv (uo.vo) at Po. Find an equation for the plane tangent to the surface at Po. Then find a Cartesian equation for the surface and sketch the surface and tangent plane together. The circular cylinder r(0,z) = (4 sin (20)) i + (8 sin²0) j+z k at the point π Po (2√3,6,0) corresponding to (0,z) = 3 An equation for the plane tangent to the surface at Po is (Type an equation using x, y, and z as the variables.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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2. A cartesian equation for the surface is?

3. Draw the graph

 

 

The tangent plane at a point Po (f(uovo) 9 (uovo).h (uo.vo)) on a
parametrized surface r(u,v) = f(u,v) i + g(u,v) j+h(u,v) k is the plane through
Po normal to the vector ru (uovo) xrv (uo,vo), the cross product of the
tangent vectors ru (40.vo) and rv (uo.vo) at Po. Find an equation for the
plane tangent to the surface at Po. Then find a Cartesian equation for the
surface and sketch the surface and tangent plane together.
The circular cylinder r(0,z) = (4 sin (20)) i + (8 sin²0) j+z k at the point
π
Po (2√3,6,0) corresponding to (0,z) =
3
An equation for the plane tangent to the surface at Po is
(Type an equation using x, y, and z as the variables.)
Transcribed Image Text:The tangent plane at a point Po (f(uovo) 9 (uovo).h (uo.vo)) on a parametrized surface r(u,v) = f(u,v) i + g(u,v) j+h(u,v) k is the plane through Po normal to the vector ru (uovo) xrv (uo,vo), the cross product of the tangent vectors ru (40.vo) and rv (uo.vo) at Po. Find an equation for the plane tangent to the surface at Po. Then find a Cartesian equation for the surface and sketch the surface and tangent plane together. The circular cylinder r(0,z) = (4 sin (20)) i + (8 sin²0) j+z k at the point π Po (2√3,6,0) corresponding to (0,z) = 3 An equation for the plane tangent to the surface at Po is (Type an equation using x, y, and z as the variables.)
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