The image presents a table and a probability question related to the age distribution of moviegoers. The table contains the following information:**Age Distribution of Moviegoers:**- Ages 12-24: 920 moviegoers- Ages 25-44: 950 moviegoers- Ages 45-64: 790 moviegoers- Ages 65-74: 200 moviegoersThe total sample size is 2860 moviegoers, aged from 12 to 74.**Problem Statement:**The task is to find the probability, expressed as a simplified fraction, that a randomly selected moviegoer is younger than 65 years old.**Solution Explanation:**To find the probability, add the number of moviegoers in age groups under 65 (12-24, 25-44, and 45-64) and divide by the total number of moviegoers.- Total number of moviegoers younger than 65: 920 + 950 + 790 = 2660The probability that a randomly selected moviegoer is less than 65 years old is:\[\frac{2660}{2860}\]This fraction can be simplified by dividing both the numerator and the denominator by their greatest common divisor.**Final Output:**The probability is \( \frac{133}{143} \).(Type an integer or a simplified fraction.)

Given that Random sample size in age moviegoers n=2860 And the Age distribution of Moviegoers ages are given in the table Using this table we have to find the probability that the Moviegoers age is less than 65

Answered: The table shows the distribution, by…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

The accompanying table shows the numbers of male and female students in a particular country who received bachelor's degrees in business in a recent year. Complete parts (a) and (b) below. Click the icon to view the data on business degrees. (a) Find the probability that a randomly selected student is male, given that the student received a business degree. The probability that a randomly selected student is male, given that the student received a business degree, is (Round to three decimal places as needed.) (b) Find the probability that a randomly selected student received a business degree, given that the student is female. The probability that a randomly selected student received a business degree, given that the student is female, is (Round to three decimal places as needed.) Business graduates Business degrees Nonbusiness degrees Total Male 192,167 616,454 808,621 1,056,907 1,865,528 Female 173,249 883,658 Total 365,416 1,500,112
A. A recent study found that 2% of Americans admitted they had driven while intoxicated in the prior month. If a problem asks you to find the probability that 200 or fewer people in a population of 10,000 drive under the influence of alcohol, how do you solve the problem after finding the probability in the z-table? A. Subtract one from the probability you find in the z-score tables B. The probability that equates to the z-score is the answer C. Tis problem cannot be answered with the z-tables D. Take the probability you find in the z-score tables and subtract from one
What would be the correct way of doing this?
The table shows the distribution, by age, of a random sample of 3090 moviegoers ages 12-74. If one moviegoer is randomly selected from this population, find the probability, expressed as a simplified fraction, that the moviegoer is not in the 65-74 age range. The probability is (Type an integer or a simplified fraction.) Age Distribution of Moviegoers Number 1300 Ages 12-24 25-44 45-64 65-74 940 600 250
The average fruit fly will lay 377 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 367, 374, 364, 388, 407, 369, 375, 362, 403, 383, 381, 391, 371 What can be concluded at the the αα = 0.10 level of significance level of significance? The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)
The table shows the distribution, by age, of a random sample of 3120 moviegoers ages 12-74. If one moviegoer is randomly selected from this population, find the probability, expressed as a simplified fraction, that the moviegoer is not in the 45-64 age range. The probability is (Type an integer or a simplified fraction.) Age Distribution of Moviegoers Ages Number 12-24 610 25-44 1270 45-64 950 290 65-74
A sample of n-4 scores has a mean of M-8. If one new score with a value of X - 3 is added to the sample. what will be the value for the new mean? OM-8 O Cannot be determined with the information provided OM-7 OM-875
The average fruit fly will lay 375 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 379, 406, 378, 394, 369, 369, 402, 383, 367, 357, 401, 407, 357, 394, 367 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: H1: C. The test statistic (please show your answer to 3 decimal places.) d. The p-value (Please show your answer %D to 4 decimal places.)
Find the mean and variance of the number of games in the World Series. Assume we have two teams, A and B. Recall that it is won by the first team to win four out of the seven games and assume that the outcomes are determined by flipping a coin.
The height (in inches) of a random sample of players in NCAA Division 1 basketball teams is shown to the left. x 75 80 75 87 77 77 67 83 77 80 73 82 73 71 80 76 72 78 68 74 74 72 76 86 77 77 78 10 Variance of the height: s² = ________. a 25.53 b 24.08 c 22.72 d 21.88
3. Help
Side-by-Side The battery manufacturer Varta sells a car battery with 800 Find the probability that 9 or fewer cars will start. cold-cranking amps and advertises great performance even in bitterly cold weather. Varta claims that after sitting on a (Use decimal notation. Use Appendix Table 1. Give your answer to four decimal places.) frozen Minnesota lake for 10 days at temperatures below 32°F, this battery will still have enough power to start a car. Suppose the actual probability of starting a car following this experiment is 0.75, and 15 randomly selected cars probability: (equipped with this battery) are subjected to these grueling conditions.

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS