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- The following contingency table shows the cross tabulation of data collected for a company that was studying their employees. Data was collected on the gender (male/female) and their position (manager/non-manager). Manager Non-Manager Total Male 15 25 40 Female 20 40 60 Total 35 65 100 Calculate the probability that a randomly selected employee is female OR a manager.The percentage of mechanical-, civil-, aeronautical-, industrial-, and chemical-engineer- ing students in the course, Engineering Mathematics, is, respectively, 25, 20, 15, 22, and 18. The probability of a mechanical-, civil-, aeronautical-, industrial-, and chemical-en- gineering students getting the grade A is 0.7, 0.6, 0.8, 0.5, and 0.65, respectively. If a student chosen at random at the end of the semester earned an A in the course, find the probability of the student belonging to mechanical engineering.Given the new fad of health consciousness, a random sample of 400 college students was asked what their preferred type of drink was and whether they took regular or sugar free. The following table gives a two-way classification of the responses. Regular Sugar free TOTALS Juice 210 95 305 Iced Coffee 75 20 95 TOTALS 285 115 400 (a) If one student is selected at random from these 400 students, find the probability that this student (i) Prefers sugar free drinks (ii) Prefers juice (iii) Prefers regular juice (iv) Prefers juice given that it is a sugar free drink. (v) Prefers iced coffee or that drinks must be sugar free. (b) Are the events 'prefers juice' and 'prefers sugar free drinks' independent? Use probabilities to state your answer.
- The table below shows the results of a survey that asked 1058 adults from a certain country if they favored or opposed a tax to fund education. A person is selected at random. Support Oppose Unsure Total Males 153 333 9 495 Females 230 303 30 563 Total 383 636 39 1058 Find the probability that the person is not unsure or is female. P(is not unsure or is female)=Here is the probability model for the blood type of a randomly chosen person in the United States: Blood Type OA BAB Probability 0.2 0.47 0.11 ?The following table shows the distribution of murders by type of weapon for murder cases in a particular country over the past 12 years. Complete parts (a) through (e). (b) What is the probability that a randomly selected murder resulted from a rifle or shotgun? (Type a decimal rounded to three decimal places as needed.) P(rifle or shotgun) = Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice. OA. If 1000 murders were randomly selected, exactly of them would have resulted from a rifle or shotgun. B. If 1000 murders were randomly selected, we would expect about of the to have resulted from a rifle or shoto (c) What is the probability that a randomly selected murder resulted from a handgun, rifle, or shotgun? P(handgun, rifle, or shotgun) = (Type a decimal rounded to three decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice. OA. If 1000 murders…
- Data was collected and placed into the following table. Brown eyes Blue eyes male 10 13 female 14 15 if someone who participated in the study is randomly selected, find the following probabilities. ( please use fractions and not decimals). A. P(Male B. P( female and brown eyes) C. P(Male or brown eyes) D. P( Female l blue eyes) E. P( Brown eyes l male) show work please!A poll asked people with and without children under 18 years old if they frequently experienced stress. The results are shown in the accompanying table. Complete parts (a) through (c) below. Frequently Experience Stress Yes No Total With child under 296 234 530 18 уears No child under 196 314 510 18 years Total 492 548 1040 a. Find the probability that a randomly chosen person from this group said "Yes," given that the person has a child under 18 years old. (Type an integer or decimal rounded to four decimal places as needed.) b. Find the probability that a randomly chosen person from this group said "Yes," given that the person does not have a child under 18 years old. (Type an integer or decimal rounded to four decimal places as needed.) c. Find the probability that a randomly chosen person from this group said "Yes" or had a child under 18 years old. (Type an integer or decimal rounded to four decimal places as needed.)Suppose that 30 percent of an adult population have an infectious disease and 40 percent have achronic disease. Assume that having an infectious disease is independent from having a chronicdisease. For each of the questions below perform the calculation using appropriate statisticalnotation.a. What is the probability that a person selected at random will have both diseases?b. What is the probability of having the infectious disease for people with the chronic disease?c. What is the probability of having the infectious disease for people without the chronic disease?d. What is the probability of not having the infectious disease for people with the chronicdisease?
- Mrs. Bukovac compiled the following table to compare the hand dominance of 200 Cleveland Heights High School students and what methods they prefer using to communicate with their friends. Communication method Cell phone/text In person Online 34 166 200 Total Hand Left-handed 12 13 domin ance Right-handed 43 72 51 Total 55 85 60 (a) If you choose a student at random, what is the probability they are left-handed, given that they communicate in person? (b) If you choose a student at random, are the events "left-handed" and "communicates by text" independent, based on the data above? Explain how you know.The following table gives data on the marital status of women aged 25 to 29. These proportions tell us the probability of the marital status of a randomly selected woman. Marital Status Never Married Married Widowed Divorced Proportion ??? 0.494 0.005 0.046 1) What percentage of women aged 25 to 29 have never been married? 2) What is the probability that a randomly chosen woman is not currently married?